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A-Level 化学 9701 Paper 1 选择题操卷练习（40 题・40 分・60 分钟）
练习卷 · A-Level 化学 9701
A-Level 化学 9701 Paper 1 选择题操卷练习：40 题、40 分、60 分钟，涵盖计量、酸碱、氧化还原、电化学、平衡、速率、化学键、有机化学与鉴别测试，附题目版及答案版 PDF、逐题解析与答案分布，全部题目原创，并非 CAIE 历届试题。
卷面资料 年级：A-Level（中六／GCE A Level） ｜ 科目：化学 ｜ 时限：60 分钟 ｜ 总分：40 分 ｜ 题数：40
甲部：物理化学与无机化学（第 1 至 20 题，每题 1 分，共 20 分）
每题选出一个最正确的选项。
| # | 题目 | 答案与评分要点 |
|---|---|---|
| 1 | What amount of substance is present in 4.00 g of calcium carbonate (Mr = 100.0)? A) 0.0400 mol B) 0.400 mol C) 4.00 mol D) 0.0200 mol（1 分） |
答案：A。n = m / Mr = 4.00 / 100.0 = 0.0400 mol。 |
| 2 | What volume is occupied by 0.250 mol of an ideal gas at room temperature and pressure (molar volume 24.0 dm3)? A) 3.00 dm3 B) 9.60 dm3 C) 24.0 dm3 D) 6.00 dm3（1 分） |
答案：D。V = n × 24.0 = 0.250 × 24.0 = 6.00 dm3。 |
| 3 | 5.85 g of sodium chloride (Mr = 58.5) is dissolved to make 250 cm3 of solution. What is the concentration? A) 0.400 mol dm-3 B) 0.100 mol dm-3 C) 0.0234 mol dm-3 D) 1.00 mol dm-3（1 分） |
答案：A。n = 5.85 / 58.5 = 0.100 mol；c = 0.100 / 0.250 = 0.400 mol dm-3。 |
| 4 | What is the pH of 0.010 mol dm-3 hydrochloric acid at 298 K? A) 1.00 B) 12.00 C) 0.010 D) 2.00（1 分） |
答案：D。强酸完全解离，[H+] = 0.010，pH = −log 0.010 = 2.00。 |
| 5 | What is the pH of 0.010 mol dm-3 sodium hydroxide at 298 K (Kw = 1.00 x 10-14)? A) 2.00 B) 7.00 C) 14.00 D) 12.00（1 分） |
答案：D。[OH−] = 0.010，pOH = 2.00，pH = 14.00 − 2.00 = 12.00。 |
| 6 | A weak monobasic acid has pH 3.00 in 0.100 mol dm-3 solution. What is Ka? A) 1.0 x 10-5 mol dm-3 B) 1.0 x 10-3 mol dm-3 C) 1.0 x 10-7 mol dm-3 D) 1.0 x 10-1 mol dm-3（1 分） |
答案：A。[H+] = 1.0 × 10−3；Ka = [H+]² / [HA] = 1.0 × 10−6 / 0.100 = 1.0 × 10−5。 |
| 7 | Burning 0.0250 mol of a fuel raises the temperature of 50.0 g of water by 10.0 K (c = 4.18 J g-1 K-1). What is the enthalpy change of combustion per mole? A) -2.09 kJ mol-1 B) -20.9 kJ mol-1 C) -83.6 kJ mol-1 D) -418 kJ mol-1（1 分） |
答案：C。q = 50.0 × 4.18 × 10.0 = 2090 J = 2.09 kJ；ΔH = −2.09 / 0.0250 = −83.6 kJ mol−1。 |
| 8 | 25.0 cm3 of 0.100 mol dm-3 NaOH is titrated with 0.200 mol dm-3 HCl. What volume of acid is required? A) 12.5 cm3 B) 25.0 cm3 C) 50.0 cm3 D) 6.25 cm3（1 分） |
答案：A。NaOH 摩尔数 = 25.0 × 0.100 = 2.50 mmol；体积 = 2.50 / 0.200 = 12.5 cm3。 |
| 9 | The theoretical yield of a reaction is 0.200 mol and the actual yield is 0.160 mol. What is the percentage yield? A) 20.0% B) 125% C) 160% D) 80.0%（1 分） |
答案：D。百分产率 = 0.160 / 0.200 × 100 = 80.0%。 |
| 10 | 1.60 g of a gas occupies 1.20 dm3 at room temperature and pressure (24.0 dm3 mol-1). What is its Mr? A) 16.0 B) 64.0 C) 0.800 D) 32.0（1 分） |
答案：D。n = 1.20 / 24.0 = 0.0500 mol；Mr = 1.60 / 0.0500 = 32.0。 |
| 11 | What amount of gas is present in 2.40 dm3 at room temperature and pressure (24.0 dm3 mol-1)? A) 0.0100 mol B) 1.00 mol C) 0.100 mol D) 57.6 mol（1 分） |
答案：C。n = V / 24.0 = 2.40 / 24.0 = 0.100 mol。 |
| 12 | A gas sample has p = 1.00 x 105 Pa, V = 2.40 x 10-3 m3 and T = 298 K. What is n? (R = 8.31 J K-1 mol-1) A) 0.969 mol B) 9.69 mol C) 0.0969 mol D) 0.00969 mol（1 分） |
答案：C。n = pV / RT = (1.00 × 105 × 2.40 × 10−3) / (8.31 × 298) = 240 / 2476 = 0.0969 mol。 |
| 13 | A radioisotope has a half-life of 6.0 hours. What mass remains from 8.0 g after 24 hours? A) 2.0 g B) 1.0 g C) 0.50 g D) 0.25 g（1 分） |
答案：C。24 / 6.0 = 4 个半衰期；8.0 / 2⁴ = 8.0 / 16 = 0.50 g。 |
| 14 | What is the oxidation number of chromium in the dichromate ion, Cr2O7 2-? A) +7 B) +6 C) +3 D) +12（1 分） |
答案：B。设 Cr 为 x：2x + 7(−2) = −2，2x = 12，x = +6。 |
| 15 | What is the oxidation number of sulfur in sulfuric acid, H2SO4? A) +4 B) +6 C) +2 D) -2（1 分） |
答案：B。2(+1) + x + 4(−2) = 0，x = +6。 |
| 16 | What is the electron configuration of an iron atom (Z = 26)? A) [Ar] 3d8 B) [Ar] 3d5 4s1 C) [Ar] 3d6 4s2 D) [Ar] 3d6 4s1 4p1（1 分） |
答案：C。Fe 有 26 个电子：18 个填入氩芯，余 8 个为 3d6 4s2。 |
| 17 | How many moles of ions are produced when 1 mol of Al2(SO4)3 dissolves completely? A) 2 mol B) 5 mol C) 3 mol D) 7 mol（1 分） |
答案：B。每单位产生 2 个 Al3+ 及 3 个 SO4 2−，共 5 mol 离子。 |
| 18 | A compound contains 40.0% C, 6.7% H and 53.3% O by mass. What is its empirical formula? A) C2H4O B) CH2O C) CHO D) C2H6O（1 分） |
答案：B。摩尔比 C : H : O = 40.0/12.0 : 6.7/1.0 : 53.3/16.0 = 3.33 : 6.7 : 3.33 = 1 : 2 : 1。 |
| 19 | What is the atom economy of CaCO3 -> CaO + CO2? (Mr: CaCO3 = 100.1, CaO = 56.1) A) 44.0% B) 100% C) 66.0% D) 56.0%（1 分） |
答案：D。原子经济 = 56.1 / 100.1 × 100 = 56.0%。 |
| 20 | What is the percentage by mass of nitrogen in ammonium nitrate, NH4NO3 (Mr = 80.0)? A) 17.5% B) 28.0% C) 70.0% D) 35.0%（1 分） |
答案：D。每个单位含 2 个 N：28.0 / 80.0 × 100 = 35.0%。 |
乙部：有机化学与分析（第 21 至 40 题，每题 1 分，共 20 分）
每题选出一个最正确的选项。
| # | 题目 | 答案与评分要点 |
|---|---|---|
| 21 | 0.100 mol of zinc reacts completely with excess dilute hydrochloric acid. What volume of hydrogen is produced at r.t.p. (24.0 dm3 mol-1)? A) 1.20 dm3 B) 2.40 dm3 C) 4.80 dm3 D) 24.0 dm3（1 分） |
答案：B。Zn + 2HCl -> ZnCl2 + H2，比例 1:1，n(H2) = 0.100 mol，V = 2.40 dm3。 |
| 22 | What mass of CuSO4.5H2O (Mr = 249.7) is needed for 0.0500 mol? A) 12.5 g B) 6.24 g C) 25.0 g D) 1.25 g（1 分） |
答案：A。m = n × Mr = 0.0500 × 249.7 = 12.485 g ≈ 12.5 g。 |
| 23 | 25.0 cm3 of 0.400 mol dm-3 solution is diluted to 250 cm3. What is the new concentration? A) 0.0400 mol dm-3 B) 0.400 mol dm-3 C) 0.00400 mol dm-3 D) 4.00 mol dm-3（1 分） |
答案：A。稀释 10 倍：摩尔数不变，c = 0.400 × 25.0 / 250 = 0.0400 mol dm-3。 |
| 24 | A buffer contains equal concentrations of a weak acid (pKa = 4.76) and its conjugate base. What is the pH? A) 7.00 B) 9.24 C) 4.76 D) 2.38（1 分） |
答案：C。[A−] = [HA]，pH = pKa + log(1) = 4.76。 |
| 25 | For H2 + I2 <=> 2HI, equilibrium concentrations are [H2] = 0.20, [I2] = 0.30 and [HI] = 0.60 mol dm-3. What is Kc? A) 6.0 B) 0.167 C) 10.0 D) 1.0（1 分） |
答案：A。Kc = [HI]² / ([H2][I2]) = 0.36 / 0.060 = 6.0。 |
| 26 | For a reaction with ΔH = +50.0 kJ mol-1 and ΔS = +100 J K-1 mol-1, what is ΔG at 500 K? A) +100 kJ mol-1 B) -50.0 kJ mol-1 C) +50.0 kJ mol-1 D) 0.0 kJ mol-1（1 分） |
答案：D。ΔG = ΔH − TΔS = 50.0 − 500 × 0.100 = 0.0 kJ mol−1。 |
| 27 | E(Cu2+/Cu) = +0.34 V and E(Zn2+/Zn) = -0.76 V. What is Ecell for Zn + Cu2+ -> Zn2+ + Cu? A) +0.42 V B) -1.10 V C) +1.10 V D) +0.34 V（1 分） |
答案：C。Ecell = E(阴极) − E(阳极) = 0.34 − (−0.76) = +1.10 V。 |
| 28 | How much charge is needed to deposit 2.00 mol of copper from Cu2+? (F = 96 500 C mol-1) A) 193 000 C B) 386 000 C C) 96 500 C D) 772 000 C（1 分） |
答案：B。Cu2+ + 2e− -> Cu，需 4.00 mol 电子：4.00 × 96 500 = 386 000 C。 |
| 29 | A current of 0.500 A flows for 1930 s through copper(II) sulfate solution. What mass of copper is deposited? (Ar Cu = 63.5) A) 0.635 g B) 0.318 g C) 0.159 g D) 1.27 g（1 分） |
答案：B。Q = 0.500 × 1930 = 965 C；n(e−) = 0.0100 mol；n(Cu) = 0.00500 mol；m = 0.318 g。 |
| 30 | Doubling [A] doubles the initial rate, while doubling [B] has no effect. Which is the rate equation? A) rate = k[A]2 B) rate = k[A][B] C) rate = k[B] D) rate = k[A]（1 分） |
答案：D。速率与 [A] 成正比、与 [B] 无关，所以 rate = k[A]。 |
| 31 | What are the units of the rate constant for rate = k[A][B] (overall second order)? A) s-1 B) dm3 mol-1 s-1 C) mol dm-3 s-1 D) dm6 mol-2 s-1（1 分） |
答案：B。mol dm−3 s−1 = k (mol dm−3)²，故 k 的单位为 dm3 mol−1 s−1。 |
| 32 | Why does a small rise in temperature greatly increase the rate of a reaction? A) The activation energy falls sharply B) The concentration of reactants rises C) A larger proportion of molecules has energy greater than the activation energy. D) The molecules become smaller（1 分） |
答案：C。温度上升令能量分布右移，超过活化能的分子比例大幅增加。 |
| 33 | What is the bond angle in an ammonia molecule? A) 107 degrees B) 109.5 degrees C) 120 degrees D) 90 degrees（1 分） |
答案：A。氨的氮原子有一对孤对电子，排斥较强，键角为 107°。 |
| 34 | What is the shape of the SF6 molecule? A) Tetrahedral B) Trigonal bipyramidal C) Octahedral D) Square planar（1 分） |
答案：C。硫与六个氟形成六个电子域，无孤对电子，故为八面体。 |
| 35 | What are the shape and bond angle of BF3? A) Pyramidal, 107 degrees B) Tetrahedral, 109.5 degrees C) Trigonal planar, 120 degrees D) Linear, 180 degrees（1 分） |
答案：C。硼有三个键对、无孤对电子，故为平面三角形，键角 120°。 |
| 36 | How many structural isomers have the molecular formula C4H10? A) 1 B) 2 C) 3 D) 4（1 分） |
答案：B。丁烷与 2-甲基丙烷，共 2 个结构异构物。 |
| 37 | How many non-cyclic structural isomers (ignoring cis-trans) have the formula C4H8? A) 3 B) 2 C) 4 D) 5（1 分） |
答案：A。丁-1-烯、丁-2-烯及 2-甲基丙-1-烯，共 3 个。 |
| 38 | What is the major product when hydrogen bromide is added to propene? A) 1-bromopropane B) 1,2-dibromopropane C) propan-2-ol D) 2-bromopropane（1 分） |
答案：D。按马氏规则，氢加在含氢较多的碳上，溴加在中间碳，得 2-溴丙烷。 |
| 39 | Propan-1-ol is refluxed with excess acidified potassium dichromate(VI). What is the organic product? A) Propanoic acid B) Propanal C) Propanone D) Propene（1 分） |
答案：A。一级醇在回流及过量氧化剂下先成醛，再氧化为丙酸。 |
| 40 | Which reagent gives an orange precipitate with a carbonyl compound? A) Tollens’ reagent B) 2,4-dinitrophenylhydrazine C) Fehling’s solution D) Bromine water（1 分） |
答案：B。2,4-二硝基苯肼与醛及酮均生成橙色沉淀。 |
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