S4 Chemistry: Periodic Table and Trends prep guide | Atomic radius, ionisation energy and metallic character
- 2026-11-01
Students say metallic character falls across a period, then stall when asked why magnesium has a higher first ionisation energy than aluminium. Every trend in this lesson hangs on one cause: nuclear charge against shielding.
01 Prerequisites (3-minute check)
If any of these fails, fix it before the lesson starts.
| Skill | Quick check | Pass mark |
|---|---|---|
| Atomic structure | Electron arrangement of sodium | 2, 8, 1 |
| Ions | Where the charges on Na+ and Cl- come from | Gain or loss of electrons |
| Symbols | The eight elements of period 3 | Na Mg Al Si P S Cl Ar |
02 Lesson flow (60 minutes)
| Time | Stage | Tutor does | Student does |
|---|---|---|---|
| 0-12 min | How the table is built | Rows count shells, columns count outer electrons | Same group, similar chemistry |
| 12-26 min | Atomic radius trend | Na 186 pm down to Cl 99 pm | Narrows by 1.88 times |
| 26-40 min | First ionisation energy | Na 496 up to Ar 1521 kJ/mol | Cl / Na = 2.52 |
| 40-50 min | The two exceptions | Al below Mg by 160, S below P by 12 kJ/mol | Electron arrangement stability |
| 50-56 min | Oxides and metallic character | Si melts at 1414 C, P at only 44 C | Ionic gives way to covalent |
| 56-60 min | Exit check | Three questions collected | Done independently |
03 Teaching script (read it out)
Scene 1: The table is an electron-arrangement map, not a list
Across period 3 sodium (2, 8, 1) becomes argon (2, 8, 8). The outer count climbs from one to eight, so the character shifts from reactive metal through the metalloid silicon to a noble gas.
The transition metals form their own block because the 3d subshell fills after 4s, which is why they show variable oxidation states, coloured ions and catalytic behaviour.
One line to remember: position fixes the arrangement, the arrangement fixes the properties. No trend needs to be memorised once that chain is in place.
Task: write the electron arrangements of potassium (period 4, group 1) and bromine (period 4, group 7) and give one property of each.
Scene 2: Radius and ionisation energy: two faces of one cause
Down a group an extra shell appears, shielding jumps, the radius grows and the first ionisation energy falls.
First ionisation energies in period 3: Na 496, Mg 738, Al 578, Si 786, P 1012, S 1000, Cl 1251 and Ar 1521 kJ/mol. The trend is upwards overall, with chlorine 2.52 times sodium.
Two exceptions must be taught explicitly: aluminium sits 160 kJ/mol below magnesium because its electron comes from a singly occupied 3p orbital, easier to remove than a full 3s pair; sulfur sits 12 kJ/mol below phosphorus because the 3p3 half-filled set is extra stable and sulfur must also overcome a paired electron repulsion.
Task: explain the radius trend with “charge up, shielding unchanged”, then explain the aluminium exception using the 3p electron.
Scene 3: Reading properties off the position: oxides, melting points and bonding
Melting points show the bonding change best: Na 98 C, Mg 650 C and Al 660 C rise with metallic bonding strength, Si peaks at 1414 C as a giant covalent network, then P collapses to 44 C, S 115 C, Cl2 -101 C as simple molecular solids held only by van der Waals forces, with Ar at -189 C as single atoms. The 1,370 C gap between silicon and phosphorus is the boundary between bonding types.
Electronegativity: Na 0.93 and Cl 3.16 differ by 2.23, and a gap above roughly 1.8 points to ionic bonding, which is why NaCl is ionic while CCl4 (about 0.5) is covalent.
Metallic character means the tendency to lose electrons, falling across a period and rising down a group, exactly mirroring the ionisation-energy trend.
Task: order MgO, SiO2 and SO3 by oxide character and write one equation each with water or alkali.
04 Question types and worked steps
| Type | Example | Steps | Answer |
|---|---|---|---|
| Trend | Radius and ionisation energy | Locate period and group, then argue charge and shielding | 186 to 99 pm |
| Exception | Irregular ionisation energy | Write the electron arrangement first | Al 160 kJ/mol lower |
| Inference | An unknown element | Outer electrons from the position | Same group, similar chemistry |
| Bonding | Oxides and melting points | Sort into metal, non-metal and metalloid | Si 1414 C against P 44 C |
The three trends must agree: radius falls, ionisation energy rises and metallic character falls from left to right. A student claiming radius and ionisation energy both rise has contradicted themselves.
Magnitude check: first ionisation energies lie between a few hundred and about two thousand kJ/mol, so 4.96 or 49,600 signals a unit slip, since 496 kJ/mol is 496,000 J/mol.
An exception does not overturn the trend: the 160 and 12 kJ/mol dips are far smaller than the overall rise across the period, so “trending upwards” stays correct.
05 Independent practice (3 questions)
| Question | Answer | What to watch |
|---|---|---|
| Largest and smallest radius in period 3 | Na at 186 pm, Cl at 99 pm | Shrinks left to right |
| Ratio of Cl to Na first ionisation energy | 2.52 | 1251 / 496 |
| Why aluminium is below magnesium | 160 kJ/mol lower | A single 3p electron leaves more easily |
| Melting point gap between Si and P | 1,370 C | Giant covalent against simple molecular |
06 Common mistakes and what to say
| Mistake | Student writes | Say this |
|---|---|---|
| Swapping group and period | Calling group 3 a row | Rows are periods, columns are groups. Swap them and most of the paper collapses. |
| Answering “because that is the trend” | No mention of charge or shielding | The trend is the result. I want the cause: charge up, shielding unchanged. |
| Ignoring the exceptions | Claiming ionisation energy always rises left to right | It rises overall, but aluminium and sulfur are exceptions and a good answer says so. |
| Explaining melting point with radius | Saying silicon melts high because its atoms are small | Melting point follows bonding type. Silicon is a giant covalent network, so radius is not the argument. |
07 Homework (paper, section and question numbers)
- Secondary Chemistry chapter index — All chapters
- Chemistry practice paper — Periodic table questions 5 to 10
08 Exit check (last 5 minutes)
| Question | Answer | Decision |
|---|---|---|
| Radius trend across period 3 | Falls left to right | Correct means bonding comes next |
| Why Al is below Mg | A single 3p electron | Wrong means redo the exceptions |
| Why NaCl is ionic | Electronegativity gap 2.23, above 1.8 | Two errors means restart the first act |
09 Tutor FAQ
Why do noble gases have the highest ionisation energies?
The outer shell is already full, so removing an electron breaks a stable octet and costs a great deal of energy.
Textbooks give different radius values, so which is right?
Sources use different definitions (metallic, covalent, van der Waals). The trend is what matters, and in an exam use the data given.
How large must an electronegativity gap be for ionic bonding?
There is no sharp cut-off; about 1.8 is a common guide, and lattice energy and physical state decide the rest.
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A TutorZone lesson-prep guide. Written by the TutorZone team; questions and lesson flow are original and are not taken from any school or publisher material.


