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A-Level 化學 9701 Paper 1 選擇題操卷練習（40 題・40 分・60 分鐘）
練習卷 · A-Level 化學 9701
A-Level 化學 9701 Paper 1 選擇題操卷練習：40 題、40 分、60 分鐘，涵蓋計量、酸鹼、氧化還原、電化學、平衡、速率、化學鍵、有機化學與鑑別測試，附題目版及答案版 PDF、逐題解析與答案分佈，全部題目原創，並非 CAIE 歷屆試題。
卷面資料 年級：A-Level（中六／GCE A Level） ｜ 科目：化學 ｜ 時限：60 分鐘 ｜ 總分：40 分 ｜ 題數：40
甲部：物理化學與無機化學（第 1 至 20 題，每題 1 分，共 20 分）
每題選出一個最正確的選項。
| # | 題目 | 答案與評分要點 |
|---|---|---|
| 1 | What amount of substance is present in 4.00 g of calcium carbonate (Mr = 100.0)? A) 0.0400 mol B) 0.400 mol C) 4.00 mol D) 0.0200 mol（1 分） |
答案：A。n = m / Mr = 4.00 / 100.0 = 0.0400 mol。 |
| 2 | What volume is occupied by 0.250 mol of an ideal gas at room temperature and pressure (molar volume 24.0 dm3)? A) 3.00 dm3 B) 9.60 dm3 C) 24.0 dm3 D) 6.00 dm3（1 分） |
答案：D。V = n × 24.0 = 0.250 × 24.0 = 6.00 dm3。 |
| 3 | 5.85 g of sodium chloride (Mr = 58.5) is dissolved to make 250 cm3 of solution. What is the concentration? A) 0.400 mol dm-3 B) 0.100 mol dm-3 C) 0.0234 mol dm-3 D) 1.00 mol dm-3（1 分） |
答案：A。n = 5.85 / 58.5 = 0.100 mol；c = 0.100 / 0.250 = 0.400 mol dm-3。 |
| 4 | What is the pH of 0.010 mol dm-3 hydrochloric acid at 298 K? A) 1.00 B) 12.00 C) 0.010 D) 2.00（1 分） |
答案：D。強酸完全解離，[H+] = 0.010，pH = −log 0.010 = 2.00。 |
| 5 | What is the pH of 0.010 mol dm-3 sodium hydroxide at 298 K (Kw = 1.00 x 10-14)? A) 2.00 B) 7.00 C) 14.00 D) 12.00（1 分） |
答案：D。[OH−] = 0.010，pOH = 2.00，pH = 14.00 − 2.00 = 12.00。 |
| 6 | A weak monobasic acid has pH 3.00 in 0.100 mol dm-3 solution. What is Ka? A) 1.0 x 10-5 mol dm-3 B) 1.0 x 10-3 mol dm-3 C) 1.0 x 10-7 mol dm-3 D) 1.0 x 10-1 mol dm-3（1 分） |
答案：A。[H+] = 1.0 × 10−3；Ka = [H+]² / [HA] = 1.0 × 10−6 / 0.100 = 1.0 × 10−5。 |
| 7 | Burning 0.0250 mol of a fuel raises the temperature of 50.0 g of water by 10.0 K (c = 4.18 J g-1 K-1). What is the enthalpy change of combustion per mole? A) -2.09 kJ mol-1 B) -20.9 kJ mol-1 C) -83.6 kJ mol-1 D) -418 kJ mol-1（1 分） |
答案：C。q = 50.0 × 4.18 × 10.0 = 2090 J = 2.09 kJ；ΔH = −2.09 / 0.0250 = −83.6 kJ mol−1。 |
| 8 | 25.0 cm3 of 0.100 mol dm-3 NaOH is titrated with 0.200 mol dm-3 HCl. What volume of acid is required? A) 12.5 cm3 B) 25.0 cm3 C) 50.0 cm3 D) 6.25 cm3（1 分） |
答案：A。NaOH 摩爾數 = 25.0 × 0.100 = 2.50 mmol；體積 = 2.50 / 0.200 = 12.5 cm3。 |
| 9 | The theoretical yield of a reaction is 0.200 mol and the actual yield is 0.160 mol. What is the percentage yield? A) 20.0% B) 125% C) 160% D) 80.0%（1 分） |
答案：D。百分產率 = 0.160 / 0.200 × 100 = 80.0%。 |
| 10 | 1.60 g of a gas occupies 1.20 dm3 at room temperature and pressure (24.0 dm3 mol-1). What is its Mr? A) 16.0 B) 64.0 C) 0.800 D) 32.0（1 分） |
答案：D。n = 1.20 / 24.0 = 0.0500 mol；Mr = 1.60 / 0.0500 = 32.0。 |
| 11 | What amount of gas is present in 2.40 dm3 at room temperature and pressure (24.0 dm3 mol-1)? A) 0.0100 mol B) 1.00 mol C) 0.100 mol D) 57.6 mol（1 分） |
答案：C。n = V / 24.0 = 2.40 / 24.0 = 0.100 mol。 |
| 12 | A gas sample has p = 1.00 x 105 Pa, V = 2.40 x 10-3 m3 and T = 298 K. What is n? (R = 8.31 J K-1 mol-1) A) 0.969 mol B) 9.69 mol C) 0.0969 mol D) 0.00969 mol（1 分） |
答案：C。n = pV / RT = (1.00 × 105 × 2.40 × 10−3) / (8.31 × 298) = 240 / 2476 = 0.0969 mol。 |
| 13 | A radioisotope has a half-life of 6.0 hours. What mass remains from 8.0 g after 24 hours? A) 2.0 g B) 1.0 g C) 0.50 g D) 0.25 g（1 分） |
答案：C。24 / 6.0 = 4 個半衰期；8.0 / 2⁴ = 8.0 / 16 = 0.50 g。 |
| 14 | What is the oxidation number of chromium in the dichromate ion, Cr2O7 2-? A) +7 B) +6 C) +3 D) +12（1 分） |
答案：B。設 Cr 為 x：2x + 7(−2) = −2，2x = 12，x = +6。 |
| 15 | What is the oxidation number of sulfur in sulfuric acid, H2SO4? A) +4 B) +6 C) +2 D) -2（1 分） |
答案：B。2(+1) + x + 4(−2) = 0，x = +6。 |
| 16 | What is the electron configuration of an iron atom (Z = 26)? A) [Ar] 3d8 B) [Ar] 3d5 4s1 C) [Ar] 3d6 4s2 D) [Ar] 3d6 4s1 4p1（1 分） |
答案：C。Fe 有 26 個電子：18 個填入氬芯，餘 8 個為 3d6 4s2。 |
| 17 | How many moles of ions are produced when 1 mol of Al2(SO4)3 dissolves completely? A) 2 mol B) 5 mol C) 3 mol D) 7 mol（1 分） |
答案：B。每單位產生 2 個 Al3+ 及 3 個 SO4 2−，共 5 mol 離子。 |
| 18 | A compound contains 40.0% C, 6.7% H and 53.3% O by mass. What is its empirical formula? A) C2H4O B) CH2O C) CHO D) C2H6O（1 分） |
答案：B。摩爾比 C : H : O = 40.0/12.0 : 6.7/1.0 : 53.3/16.0 = 3.33 : 6.7 : 3.33 = 1 : 2 : 1。 |
| 19 | What is the atom economy of CaCO3 -> CaO + CO2? (Mr: CaCO3 = 100.1, CaO = 56.1) A) 44.0% B) 100% C) 66.0% D) 56.0%（1 分） |
答案：D。原子經濟 = 56.1 / 100.1 × 100 = 56.0%。 |
| 20 | What is the percentage by mass of nitrogen in ammonium nitrate, NH4NO3 (Mr = 80.0)? A) 17.5% B) 28.0% C) 70.0% D) 35.0%（1 分） |
答案：D。每個單位含 2 個 N：28.0 / 80.0 × 100 = 35.0%。 |
乙部：有機化學與分析（第 21 至 40 題，每題 1 分，共 20 分）
每題選出一個最正確的選項。
| # | 題目 | 答案與評分要點 |
|---|---|---|
| 21 | 0.100 mol of zinc reacts completely with excess dilute hydrochloric acid. What volume of hydrogen is produced at r.t.p. (24.0 dm3 mol-1)? A) 1.20 dm3 B) 2.40 dm3 C) 4.80 dm3 D) 24.0 dm3（1 分） |
答案：B。Zn + 2HCl -> ZnCl2 + H2，比例 1:1，n(H2) = 0.100 mol，V = 2.40 dm3。 |
| 22 | What mass of CuSO4.5H2O (Mr = 249.7) is needed for 0.0500 mol? A) 12.5 g B) 6.24 g C) 25.0 g D) 1.25 g（1 分） |
答案：A。m = n × Mr = 0.0500 × 249.7 = 12.485 g ≈ 12.5 g。 |
| 23 | 25.0 cm3 of 0.400 mol dm-3 solution is diluted to 250 cm3. What is the new concentration? A) 0.0400 mol dm-3 B) 0.400 mol dm-3 C) 0.00400 mol dm-3 D) 4.00 mol dm-3（1 分） |
答案：A。稀釋 10 倍：摩爾數不變，c = 0.400 × 25.0 / 250 = 0.0400 mol dm-3。 |
| 24 | A buffer contains equal concentrations of a weak acid (pKa = 4.76) and its conjugate base. What is the pH? A) 7.00 B) 9.24 C) 4.76 D) 2.38（1 分） |
答案：C。[A−] = [HA]，pH = pKa + log(1) = 4.76。 |
| 25 | For H2 + I2 <=> 2HI, equilibrium concentrations are [H2] = 0.20, [I2] = 0.30 and [HI] = 0.60 mol dm-3. What is Kc? A) 6.0 B) 0.167 C) 10.0 D) 1.0（1 分） |
答案：A。Kc = [HI]² / ([H2][I2]) = 0.36 / 0.060 = 6.0。 |
| 26 | For a reaction with ΔH = +50.0 kJ mol-1 and ΔS = +100 J K-1 mol-1, what is ΔG at 500 K? A) +100 kJ mol-1 B) -50.0 kJ mol-1 C) +50.0 kJ mol-1 D) 0.0 kJ mol-1（1 分） |
答案：D。ΔG = ΔH − TΔS = 50.0 − 500 × 0.100 = 0.0 kJ mol−1。 |
| 27 | E(Cu2+/Cu) = +0.34 V and E(Zn2+/Zn) = -0.76 V. What is Ecell for Zn + Cu2+ -> Zn2+ + Cu? A) +0.42 V B) -1.10 V C) +1.10 V D) +0.34 V（1 分） |
答案：C。Ecell = E(陰極) − E(陽極) = 0.34 − (−0.76) = +1.10 V。 |
| 28 | How much charge is needed to deposit 2.00 mol of copper from Cu2+? (F = 96 500 C mol-1) A) 193 000 C B) 386 000 C C) 96 500 C D) 772 000 C（1 分） |
答案：B。Cu2+ + 2e− -> Cu，需 4.00 mol 電子：4.00 × 96 500 = 386 000 C。 |
| 29 | A current of 0.500 A flows for 1930 s through copper(II) sulfate solution. What mass of copper is deposited? (Ar Cu = 63.5) A) 0.635 g B) 0.318 g C) 0.159 g D) 1.27 g（1 分） |
答案：B。Q = 0.500 × 1930 = 965 C；n(e−) = 0.0100 mol；n(Cu) = 0.00500 mol；m = 0.318 g。 |
| 30 | Doubling [A] doubles the initial rate, while doubling [B] has no effect. Which is the rate equation? A) rate = k[A]2 B) rate = k[A][B] C) rate = k[B] D) rate = k[A]（1 分） |
答案：D。速率與 [A] 成正比、與 [B] 無關，所以 rate = k[A]。 |
| 31 | What are the units of the rate constant for rate = k[A][B] (overall second order)? A) s-1 B) dm3 mol-1 s-1 C) mol dm-3 s-1 D) dm6 mol-2 s-1（1 分） |
答案：B。mol dm−3 s−1 = k (mol dm−3)²，故 k 的單位為 dm3 mol−1 s−1。 |
| 32 | Why does a small rise in temperature greatly increase the rate of a reaction? A) The activation energy falls sharply B) The concentration of reactants rises C) A larger proportion of molecules has energy greater than the activation energy. D) The molecules become smaller（1 分） |
答案：C。溫度上升令能量分佈右移，超過活化能的分子比例大幅增加。 |
| 33 | What is the bond angle in an ammonia molecule? A) 107 degrees B) 109.5 degrees C) 120 degrees D) 90 degrees（1 分） |
答案：A。氨的氮原子有一對孤對電子，排斥較強，鍵角為 107°。 |
| 34 | What is the shape of the SF6 molecule? A) Tetrahedral B) Trigonal bipyramidal C) Octahedral D) Square planar（1 分） |
答案：C。硫與六個氟形成六個電子域，無孤對電子，故為八面體。 |
| 35 | What are the shape and bond angle of BF3? A) Pyramidal, 107 degrees B) Tetrahedral, 109.5 degrees C) Trigonal planar, 120 degrees D) Linear, 180 degrees（1 分） |
答案：C。硼有三個鍵對、無孤對電子，故為平面三角形，鍵角 120°。 |
| 36 | How many structural isomers have the molecular formula C4H10? A) 1 B) 2 C) 3 D) 4（1 分） |
答案：B。丁烷與 2-甲基丙烷，共 2 個結構異構物。 |
| 37 | How many non-cyclic structural isomers (ignoring cis-trans) have the formula C4H8? A) 3 B) 2 C) 4 D) 5（1 分） |
答案：A。丁-1-烯、丁-2-烯及 2-甲基丙-1-烯，共 3 個。 |
| 38 | What is the major product when hydrogen bromide is added to propene? A) 1-bromopropane B) 1,2-dibromopropane C) propan-2-ol D) 2-bromopropane（1 分） |
答案：D。按馬氏規則，氫加在含氫較多的碳上，溴加在中间碳，得 2-溴丙烷。 |
| 39 | Propan-1-ol is refluxed with excess acidified potassium dichromate(VI). What is the organic product? A) Propanoic acid B) Propanal C) Propanone D) Propene（1 分） |
答案：A。一級醇在迴流及過量氧化劑下先成醛，再氧化為丙酸。 |
| 40 | Which reagent gives an orange precipitate with a carbonyl compound? A) Tollens’ reagent B) 2,4-dinitrophenylhydrazine C) Fehling’s solution D) Bromine water（1 分） |
答案：B。2,4-二硝基苯肼與醛及酮均生成橙色沉澱。 |
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