HKDSE Physical Education Paper 1 Mock Paper | 10 Questions, 100 Marks, 2 Hours

2026-11-01

HKDSE Physical Education

HKDSE Physical Education Paper 1 mock: 10 questions, 100 marks, 120 minutes, covering energy systems in a 400 m sprint, the calf lever and tendon force, VO2max and BMI from the 12-minute run, resistance training loads and target heart rates, sweat rate and carbohydrate intake, a basketball projectile, cardiac output, pre-competition anxiety statistics, RICE first aid, and a discussion on sports facilities, with marking notes for every question.

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Paper details　Level: HKDSE (S6) | Subject: Physical Education | Time: 2 hours | Marks: 100 | Questions: 10

Section A (Questions 1 to 5, 50 marks)

Answer ALL questions. In calculations show the formula, the substitution and the unit, and give answers to the accuracy asked; in discussion questions state a position and support it with reasons.

#	Question	Answer and marking notes
1	A 70 kg sprinter completes 400 m in 55 seconds. (a) Calculate the average speed in m/s and the kinetic energy at that speed, assuming uniform speed, in joules. (b) State the main energy system used in the first 10 seconds and the one used after 60 seconds, with one feature of each. (c) Explain how the dominant energy system would change if the athlete ran a marathon instead.	Answer: (a) Speed = 400 / 55 = 7.27 m/s; kinetic energy = 0.5 x 70 x 7.27^2 = 1,851 J. (b) The ATP-CP system dominates the first 10 seconds: fastest supply, no lactic acid and very limited stores. The lactic acid system dominates from about 10 to 120 seconds: fast supply but lactic acid accumulates. (c) A marathon relies mainly on the aerobic system, which needs oxygen, supplies energy slowly but lasts for hours.
2	In a heel raise the ball of the foot is the fulcrum, the Achilles tendon attaches 0.06 m from the fulcrum and the line of action of body weight is 0.18 m from it. The athlete weighs 700 N. (a) Calculate the tendon force needed. (b) Calculate the mechanical advantage and name the class of lever. (c) If the heel rises 0.05 m, find the shortening of the tendon and the work done by the muscle.	Answer: (a) Moments about the fulcrum: F x 0.06 = 700 x 0.18, so F = 2,100 N. (b) Mechanical advantage = 0.06 / 0.18 = 0.333; it is a second class lever, so force is gained but speed and range of movement are reduced. (c) Tendon shortening = 0.05 x 0.06 / 0.18 = 0.0167 m; work = 2,100 x 0.0167 = 35 J, the same as 700 x 0.05.
3	A 17-year-old boy of mass 66 kg and height 1.72 m covers 2,400 m in the 12-minute run test. (a) Use VO2max = (distance – 504.9) / 44.73 to estimate his maximal oxygen uptake. (b) Calculate his BMI and classify it. (c) How many kilograms should he lose to reach a BMI of 22?	Answer: (a) VO2max = (2,400 – 504.9) / 44.73 = 42.37 ml/kg/min. (b) BMI = 66 / 1.72^2 = 22.31, within the normal range of 18.5 to 22.9 for Hong Kong Chinese adults. (c) Target mass = 22 x 2.9584 = 65.08 kg, so he should lose 0.92 kg.
4	A 20-year-old athlete has a bench press 1RM of 80 kg. He plans eight weeks of resistance training, three sessions a week, at 70% of 1RM, adding 5% of the load every two weeks. (a) Find the training load. (b) Find the total number of sessions. (c) Using 220 minus age, find the target heart rates at 70% and 85%. (d) Distinguish the principles of overload and progression.	Answer: (a) 80 x 70% = 56 kg. (b) 8 x 3 = 24 sessions. (c) Maximal heart rate = 200 bpm, so 70% = 140 bpm and 85% = 170 bpm. (d) Overload means training above the current level of adaptation; progression means raising the load in planned steps, here 5% every two weeks, to avoid overtraining and injury.
5	An athlete plays for 2 hours in hot weather. Body mass is 68.0 kg before and 66.2 kg after the match, and 0.4 litre of fluid is drunk. (a) Assuming no urine loss, calculate the total sweat loss and the sweat rate per hour. (b) A replacement of 150% of the loss is advised; find that volume. (c) At 60 g of carbohydrate per hour, how much is needed for the match? (d) A drink contains 6 g of sugar per 100 ml; how many millilitres supply that amount?	Answer: (a) Loss = 1.8 + 0.4 = 2.2 kg, about 2.2 litres; sweat rate = 2.2 / 2 = 1.1 litre per hour. (b) 2.2 x 150% = 3.3 litres. (c) 60 x 2 = 120 g. (d) 120 / 6 x 100 = 2,000 ml, that is 1,000 ml per hour.

Section B (Questions 6 to 10, 50 marks)

#	Question	Answer and marking notes
6	A basketball player releases the ball 2.0 m above the floor at 8.0 m/s at 45 degrees to the horizontal (g = 9.81 m/s2, air resistance neglected). (a) Find the horizontal and vertical components of velocity. (b) Find the time of flight and explain why the time rising equals the time falling. (c) Find the horizontal range. (d) Find the highest point of the ball above the floor.	Answer: (a) vx = vy = 8.0 x cos 45 = 5.66 m/s. (b) t = 2 x 5.66 / 9.81 = 1.15 s. (c) Range = 8.0^2 x sin 90 / 9.81 = 6.52 m. (d) Rise = 5.66^2 / (2 x 9.81) = 1.63 m, so the peak is 2.0 + 1.63 = 3.63 m above the floor.
7	At rest an athlete has a heart rate of 70 bpm and a stroke volume of 70 ml; at maximal exercise the values are 180 bpm and 120 ml. The arterio-venous oxygen difference rises from 50 ml per litre of blood to 150 ml per litre. (a) Calculate the cardiac output at rest and at maximal exercise. (b) Find the factor by which it rises. (c) Estimate the maximal oxygen uptake in litres per minute and per kilogram for the 70 kg athlete.	Answer: (a) Rest = 70 x 70 = 4.9 litres per minute; maximal = 180 x 120 = 21.6 litres per minute. (b) 21.6 / 4.9 = 4.41 times. (c) VO2 = 21.6 x 0.150 = 3.24 litres per minute, that is 3,240 / 70 = 46.29 ml/kg/min.
8	The pre-competition anxiety scores of five athletes are 18, 22, 25, 20 and 15. (a) Find the mean, the range and the standard deviation, using the population formula. (b) Explain the inverted-U hypothesis and use it to describe the relation between anxiety and performance. (c) Suggest two methods of reducing pre-competition anxiety. (d) Explain how SMART goal setting affects the level of pre-competition anxiety.	Answer: (a) Mean = 100 / 5 = 20; range = 25 – 15 = 10; sum of squared deviations = 58, variance = 11.6 and standard deviation = 3.41. (b) The inverted-U hypothesis states that performance rises with arousal to a moderate optimum and then falls; too little arousal gives poor motivation, too much narrows attention and increases muscle tension. (c) Imagery rehearsal and breathing relaxation, or progressive muscular relaxation and a fixed pre-performance routine. (d) Specific, measurable, achievable, relevant and time-bound goals raise confidence and focus and cut the uncertainty that drives anxiety, whereas vague or over-high goals raise it.
9	A player sprains an ankle during a match and the joint swells and hurts at once. (a) State the four steps of RICE and the purpose of each. (b) If ice is applied every 3 hours for 20 minutes, how many applications and how many minutes are there in a day? (c) Rehabilitation lasts 6 weeks with 5 sessions a week; how many sessions is that? (d) Give two objective criteria for returning to play. (e) Explain why ice should not be placed directly on the skin.	Answer: (a) Rest to prevent further damage; Ice to reduce pain and swelling; Compression to limit swelling; Elevation to assist venous return. (b) 24 / 3 = 8 applications, 8 x 20 = 160 minutes. (c) 6 x 5 = 30 sessions. (d) Hopping on one leg without pain, and range of movement or strength within 10% of the uninjured side. (e) Direct contact cools the skin far below a safe level and can cause a cold burn; wrap the ice in a thin towel and apply it for no more than 20 minutes at a time.
10	A survey of 1,200 people finds that 432 of them exercise three times a week or more. Hong Kong has about 3,000 public and private sports facilities and a population of about 7.5 million. (a) Calculate the proportion meeting the target and the number of facilities per 10,000 people. (b) How many more people in the sample would be needed to raise the proportion to 45%? (c) Comment on the claim that providing more sports facilities will raise participation, giving two arguments for and two against.	Answer: (a) 432 / 1,200 = 36%; 3,000 / 750 = 4.0 facilities per 10,000 people. (b) 45% x 1,200 = 540 people, so 108 more are needed. (c) For: better access and shorter queues raise the chance to take part. Against: participation also depends on time, income, weather and sporting culture, and new facilities need coaching and promotion, so hardware alone may not raise participation.

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