Secondary 1 Integrated Science Practice Paper: Laboratory Safety and Measurement, States of Matter, Separation Methods, Energy, Cells and Forces (100 marks)

2026-11-13

Integrated Science – Secondary 1 – Practice Paper

Secondary 1 integrated science practice paper: lab safety, measurement, states of matter, separation methods, energy, cells and forces, with full answers.

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Paper details　Secondary 1 integrated science practice paper with full answers: laboratory safety, measurement, density, states of matter, separation methods, energy, cells and forces.

Section A: Laboratory Safety and Measurement (20 marks)

A student measures an irregular stone: 40 mL of water is poured into a measuring cylinder and the level rises to 58 mL after the stone is added; the mass of the stone is 24.6 g. The laboratory also has a 0.75 kg pack of salt and a 250 mL bottle of distilled water.

#	Question	Answer and marking notes
1	Find the volume of the stone.	Answer: 58 – 40 = 18 cubic cm. (Marking: reading both levels 3, subtracting 2)
2	Find the density of the stone, correct to 2 decimal places.	Answer: density = 24.6 / 18 = 1.37 g per cubic cm. (Marking: formula 2, substitution 2, unit 1)
3	Change 0.75 kg into g, and 250 mL into cubic cm.	Answer: 0.75 x 1000 = 750 g, and 250 mL = 250 cubic cm. (Marking: 2 marks each, units 1)
4	State two safety rules when heating a test tube with a Bunsen burner.	Answer: never point the mouth of the tube at yourself or others, and hold the tube with a test tube holder while heating it evenly. (Marking: 2 marks each, clarity 1)

Section B: States of Matter and the Particle Model (16 marks)

A piece of ice is heated from -10 degrees C until it reaches 15 degrees C. The melting point of ice is 0 degrees C and the boiling point of water is 100 degrees C.

#	Question	Answer and marking notes
5	Find the rise in temperature.	Answer: 15 – (-10) = 25 degrees C. (Marking: setting up 2, answer with unit 2)
6	What happens to the ice at 0 degrees C, and does the temperature rise?	Answer: the ice melts into water, changing from solid to liquid, and the temperature stays at 0 degrees C because the energy absorbed breaks the regular arrangement of particles. (Marking: melting 2, constant temperature with reason 2)
7	What state is water in between 0 and 100 degrees C, and what happens at 100 degrees C?	Answer: water is a liquid in this range, and at 100 degrees C it boils and changes into steam. (Marking: liquid 2, boiling and change of state 2)
8	Use the particle model to explain how the particles change when heated.	Answer: the particles gain energy, move faster with more kinetic energy, and the spaces between them increase, so the substance expands. (Marking: faster motion 2, kinetic energy or spacing 2)

Section C: Separation Methods (16 marks)

At 25 degrees C, 50 g of water dissolves at most 18 g of salt. A student stirs 36 g of salt into 100 g of water.

#	Question	Answer and marking notes
9	Find the greatest mass of salt that 100 g of water dissolves at 25 degrees C.	Answer: 50 g of water dissolves 18 g, so 100 g dissolves 18 x 2 = 36 g. (Marking: scaling 2, answer 2)
10	Find the total mass of the solution formed.	Answer: 36 + 100 = 136 g, since mass is conserved. (Marking: adding 2, answer with unit 2)
11	Find the percentage by mass of salt in the solution, correct to 1 decimal place.	Answer: 36 / 136 x 100 = 26.5 percent. (Marking: formula 2, answer 2)
12	Which method recovers salt from salt water, and why can filtration not separate the mixture?	Answer: distillation or evaporation to crystallisation; the dissolved salt particles pass through the filter paper, and filtration only removes insoluble solids. (Marking: method 2, explanation 2)

Section D: Energy and Efficiency (16 marks)

A 2000 W electric kettle is used for 0.1 hour, and 576 kJ of the energy is useful for heating the water.

#	Question	Answer and marking notes
13	Find the electrical energy used by the kettle in kWh.	Answer: 2000 x 0.1 / 1000 = 0.2 kWh. (Marking: formula 2, conversion 2)
14	Change that energy into kJ.	Answer: 0.2 x 3600 = 720 kJ. (Marking: multiplying by 3600 3, unit 1)
15	Find the efficiency of the kettle.	Answer: efficiency = 576 / 720 x 100 = 80 percent. (Marking: formula 2, answer 2)
16	Name one renewable energy source and state one benefit of using it.	Answer: solar or wind energy; it is continually replaced in nature, so it is not used up, and it produces little pollution. (Marking: example 2, benefit 2)

Section E: Cells and Photosynthesis (16 marks)

A student uses a microscope to observe onion epidermal cells; the eyepiece magnifies 10 times and the objective magnifies 40 times.

#	Question	Answer and marking notes
17	Find the total magnification of the microscope.	Answer: 10 x 40 = 400 times. (Marking: multiplying 2, answer with unit 2)
18	Name three structures found in an onion epidermal cell.	Answer: cell wall, cell membrane, nucleus, cytoplasm and vacuole, any three. (Marking: 1 mark each, 1 mark for accurate names)
19	Write the word equation for photosynthesis.	Answer: carbon dioxide + water -> (light energy, chlorophyll) glucose + oxygen. (Marking: reactants 2, products 2)
20	Explain why onion epidermal cells cannot carry out photosynthesis.	Answer: these cells have no chlorophyll, so they cannot absorb light energy and cannot carry out photosynthesis. (Marking: no chlorophyll 2, link to light energy 2)

Section F: Forces and Simple Machines (16 marks)

A spring extends 2 cm for every 1 N of weight hung on it. On a lever, a 4 N weight hangs 0.3 m from the fulcrum while a force acts 0.2 m from the fulcrum on the other side. A student runs 120 m in 40 s.

#	Question	Answer and marking notes
21	Find the extension of the spring when a 6 N weight is hung on it.	Answer: 6 x 2 = 12 cm. (Marking: proportionality 2, answer with unit 2)
22	Find the moment on the left side of the lever.	Answer: moment = 4 x 0.3 = 1.2 N m. (Marking: formula 2, answer with unit 2)
23	Find the force needed on the right side to balance the lever.	Answer: 1.2 / 0.2 = 6 N. (Marking: equal moments 2, answer with unit 2)
24	Find the average speed of the student.	Answer: 120 / 40 = 3 m per s. (Marking: formula 2, answer with unit 2)

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