Secondary 5 Physical Education Practice Paper: Fitness Testing And Evaluation, Energy Systems And Sports Nutrition, Training Methods And Load Planning, Mechanics And Biomechanics, Sport Psychology And Stress Management, Sport In Society And Health Policy

Secondary 5 Physical Education Practice Paper: Fitness Testing and Evaluation, Energy Systems and Sports Nutrition, Training Methods and Load Planning, Mechanics and Biomechanics, Sport Psychology and Stress Management, Sport in Society and Health Policy

2026-11-14

Physical Education – Secondary 5 – Practice Paper

S5 PE practice paper: 24 parts in 60 minutes on shuttle-run distance, BMI, heart rate reserve, body fat, macronutrient energy, torque and range, and marking points.

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Paper details　S5 PE practice paper, 24 parts in 60 minutes, covering multi-stage run distance, BMI, Karvonen target heart rate, body fat target mass, macronutrient energy split, 1RM training tonnage, interval run pace, torque and projectile range, forearm lever force, impulse and average force, HRV monitoring, court area, hire cost and participation rate, with marking points.

Section A: Fitness Testing and Evaluation (16 marks)

Subject: S5 boy, age 16, stature 1.72 m, body mass 63.5 kg, resting heart rate 62 bpm, 68 shuttles on the 20 m multi-stage run, measured body fat 18.0 per cent.

#	Question	Answer and marking notes
1	(a) The subject completes 68 shuttles of a 20 m course; calculate the total distance in metres and name the main fitness component tested.	Answer: 68 x 20 = 1360 m. The test mainly measures cardiorespiratory endurance (aerobic capacity). Marking points: 2 marks for the distance and 2 for the component.
2	(b) Calculate the BMI to one decimal place and classify it on the adult scale where 18.5 to 22.9 is the normal range.	Answer: 63.5 / 1.72 squared = 21.5, which lies between 18.5 and 22.9 and is therefore a normal body mass. Marking points: 2 marks for the value and 2 for the class; leaving stature un-squared scores nothing.
3	(c) Estimate maximum heart rate as 220 minus age and use the Karvonen method with heart rate reserve to find the target heart rate at 70 per cent intensity, rounded to a whole number.	Answer: maximum heart rate 204 bpm, reserve 142, target 142 x 0.70 + 62 = 161 bpm. Marking points: 1 mark for maximum heart rate, 1 for the reserve and 2 for the target.
4	(d) Body fat is 18.0 per cent. Assuming only fat is lost and lean mass stays constant, calculate the target body mass for 15.0 per cent body fat and the fat mass to be lost, both to two decimal places.	Answer: fat mass 11.43 kg and lean mass 52.07 kg, so the target mass is 52.07 / 0.85 = 61.26 kg and 2.24 kg of fat must be lost. Marking points: 1 mark for lean mass, 2 for the target mass and 1 for the fat to lose.

Section B: Energy Systems and Sports Nutrition (17 marks)

Data: 100 m personal best 12.0 s; daily energy requirement 2,800 kcal with carbohydrate 60 per cent, protein 15 per cent and fat 25 per cent of energy intake.

#	Question	Answer and marking notes
5	(a) A 100 m run takes 12.0 s; calculate the average speed in m/s to two decimal places and name the energy system it mainly relies on.	Answer: 100.0 / 12.0 = 8.33 m/s, mainly powered by the ATP-PC (phosphagen) system. Marking points: 2 marks for the speed and 2 for the energy system.
6	(b) Daily intake is 2,800 kcal with carbohydrate at 60 per cent; calculate the energy from carbohydrate in kcal and the grams needed at 4 kcal per gram, as a whole number.	Answer: 2,800 x 0.60 = 1680 kcal and 1680 / 4 = 420 g. Marking points: 2 marks for the energy and 2 for the grams.
7	(c) Protein supplies 15 per cent of intake; find its energy and grams at 4 kcal per gram, then find the grams of fat at 25 per cent of intake using 9 kcal per gram to one decimal place.	Answer: protein 2,800 x 0.15 = 420 kcal and 105 g; fat 2,800 x 0.25 = 700 kcal and 77.8 g. Marking points: 2 marks for protein and 2 for fat.
8	(d) Body mass falls by 1.2 kg over a session. Replace 150 per cent of the loss; calculate the total fluid in mL and the volume of each of four equal servings.	Answer: 1.2 kg is 1,200 mL of sweat, so 1,200 x 1.5 = 1800 mL is needed and each serving is 1800 / 4 = 450 mL. Marking points: 2 marks for the conversion, 2 for the total and 1 for each serving.

Section C: Training Methods and Load Planning (16 marks)

Data: back squat 1RM 60 kg; total training time last week 320 minutes; 8 x 400 m interval repetitions at 90 s each with 90 s recovery after every repetition.

#	Question	Answer and marking notes
9	(a) Back squat 1RM is 60 kg. Using 75 per cent of 1RM for 3 sets of 10 repetitions, calculate the load used and the total training volume in kg.	Answer: 60 x 0.75 = 45 kg, so the volume is 45 x 3 x 10 = 1350 kg. Marking points: 2 marks for the load and 2 for the volume.
10	(b) Last week the athlete trained 320 minutes. Applying the rule that weekly volume rises by no more than 10 per cent, calculate the ceiling for this week in minutes.	Answer: 320 x 1.10 = 352 minutes. Marking points: 2 marks for the working and 2 for the answer; a bigger jump is an overload error.
11	(c) An interval session of 8 repetitions over 400 m at 90 s each with 90 s recovery between repetitions; calculate the total time including recovery in minutes and the average speed in m/s to two decimal places.	Answer: 8 x (90 + 90) = 1440 s = 24 minutes, and 400 / 90 = 4.44 m/s. Marking points: 2 marks for the total time and 2 for the average speed.
12	(d) Using the heart rate reserve from this paper, calculate the target heart rate range for 60 to 80 per cent intensity as whole numbers.	Answer: lower 62 + 142 x 0.60 = 147 and upper 62 + 142 x 0.80 = 176 bpm. Marking points: 2 marks each.

Section D: Mechanics and Biomechanics (18 marks)

Data: torque test with 250 N applied at a 0.32 m moment arm; standing long jump take-off speed 8.0 m/s at 45 degrees; forearm load 5.0 kg with a 0.04 m muscle arm and a 0.30 m load arm; a 60 kg runner at 8.0 m/s stopping in 0.40 s.

#	Question	Answer and marking notes
13	(a) A force of 250.0 N acts at a moment arm of 0.32 m; calculate the torque in N m to one decimal place and state how the torque changes if the moment arm doubles while the force stays the same.	Answer: 250.0 x 0.32 = 80.0 N m; doubling the arm doubles the torque to 160.0 N m. Marking points: 3 marks for the value and 2 for the explanation.
14	(b) Take-off speed is 8.0 m/s at 45 degrees and g is 9.81 m/s squared; calculate the horizontal range and the peak height, each to two decimal places.	Answer: range 8.0 squared x sin 90 / 9.81 = 6.52 m and peak height 8.0 squared x sin squared 45 / (2 x 9.81) = 1.63 m. Marking points: 2 marks each.
15	(c) A forearm carries a 5.0 kg load with a 0.04 m muscle arm and a 0.3 m load arm; calculate the muscle force needed to hold the position, in N to one decimal place.	Answer: 5.0 x 9.81 x 0.3 / 0.04 = 367.9 N, about 7.5 times the load. Marking points: 2 marks for the moment balance and 2 for the value.
16	(d) A 60.0 kg runner moves at 8.0 m/s; calculate the momentum in kg m/s and the average braking force in N when stopping in 0.4 s.	Answer: momentum 60.0 x 8.0 = 480.0 kg m/s and average force 480.0 / 0.4 = 1200 N. Marking points: 2 marks for momentum and 3 for the force.

Section E: Sport Psychology and Stress Management (15 marks)

Data: pre-competition heart rate rises from a resting 62 to 108 bpm; breathing rhythm 4 s in, 2 s hold, 6 s out; 5 km pace target improving from 5:00 to 4:30 per km over 12 weeks; imagery training 6 weeks, 4 sessions weekly, 15 minutes each; heart rate variability falls from 68 ms to 52 ms.

#	Question	Answer and marking notes
17	(a) Calculate the percentage rise in heart rate from rest to pre-competition, to one decimal place, and state which division of the autonomic nervous system it reflects.	Answer: (108 – 62) / 62 = 74.2 per cent, reflecting sympathetic activation. Marking points: 2 marks each.
18	(b) A breathing cycle is 4 s in, 2 s hold and 6 s out; calculate the cycle length in seconds and the breaths per minute.	Answer: the cycle is 12 s and 60 / 12 = 5 breaths per minute. Marking points: 2 marks each.
19	(c) Imagery training runs for 6 weeks, 4 sessions per week and 15 minutes per session; calculate the total hours.	Answer: 6 x 4 x 15 = 360 minutes = 6 hours. Marking points: 2 marks for the minutes and 1 for the conversion.
20	(d) Heart rate variability falls from 68.0 ms to 52.0 ms; calculate the fall in per cent to one decimal place and, under the rule that a fall above 10 per cent requires a volume cut, suggest one training adjustment.	Answer: (68.0 – 52.0) / 68.0 = 23.5 per cent, above the 10 per cent flag, so weekly volume should be cut, for example one fewer interval repetition or an extra recovery day. Marking points: 2 marks each.

Section F: Sport in Society and Health Policy (18 marks)

Data: a school half court of 14 m by 15 m with 24 students per lesson; community court hire at HK$520 per hour for 1.5 hours, twice weekly, over 12 weeks; 630 of 1,050 students joined a school team or interest class this year.

#	Question	Answer and marking notes
21	(a) The World Health Organization recommends 60 minutes of moderate to vigorous physical activity daily for a 13 year old; calculate the weekly total in minutes.	Answer: 60 x 7 = 420 minutes. Marking points: 3 marks for the working and 2 for the answer.
22	(b) The half court is 14.0 m by 15.0 m and a lesson has 24 students; calculate the area and the area per student in square metres to two decimal places.	Answer: 14.0 x 15.0 = 210.0 square metres and 210.0 / 24 = 8.75 square metres each. Marking points: 2 marks each.
23	(c) Hire costs HK$520 per hour for 1.5 hours, twice weekly over 12 weeks; calculate the cost per session and the total.	Answer: 520 x 1.5 = 780 per session and 780 x 2 x 12 = 18720 in total. Marking points: 2 marks each.
24	(d) Of 1050 students, 630 joined a team or interest class; calculate the participation rate to one decimal place and how many more students are needed to reach 75 per cent.	Answer: 630 / 1050 = 60.0 per cent; the 75 per cent target is 788 students, so 158 more are needed. Marking points: 2 marks for the rate, 2 for the target and 1 for the gap.

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