S6 Biology Practice Paper: Cell Structure and Enzymes, Photosynthesis and Respiration, Genetics, Ecology, Human Physiology, Biotechnology (with answers)
- 2026-11-15
S6 Biology practice paper: enzymes, photosynthesis, respiration, genetics, ecology, physiology, biotechnology; 24 parts, 100 marks, 60 minutes, full answers.
Cell Structure and Enzymes
These questions cover surface-area-to-volume ratio, enzyme reaction rate, diffusion and microscope calculation.
| # | Question | Answer and marking notes |
|---|---|---|
| 1 | For cube models of side 2 cm and side 1 cm, what is the surface-area-to-volume ratio (per cm) of each? Which is larger, and by what factor? | Answer: the 2 cm cube gives 24 / 8 = 3.0 per cm, the 1 cm cube gives 6 / 1 = 6.0 per cm; the smaller cube has 2.0 times the ratio, so diffusion supplies it more easily. |
| 2 | An enzyme catalyses 120 reaction units per minute at 30 degrees and only 90 units at 50 degrees. What is the percentage drop, and why? | Answer: a fall of 30 units, i.e. 25.0 per cent; heat denatures the enzyme so the active site no longer fits the substrate. |
| 3 | Diffusion time is proportional to the square of distance. If the distance becomes 3 times longer, by what factor does the time change? | Answer: time goes as the square of distance, and 3 squared is 9, so the time becomes 9 times longer. |
| 4 | Under 500 times magnification, a cell of actual diameter 20 micrometres has an image of what diameter in millimetres? | Answer: 20 micrometres times 500 gives 10000 micrometres, that is 1 cm or 10.0 millimetres. |
Photosynthesis and Respiration
These questions cover the stoichiometry of photosynthesis, aerobic versus anaerobic yield, and transpiration loss.
| # | Question | Answer and marking notes |
|---|---|---|
| 5 | In the photosynthesis equation, 12 moles of carbon dioxide produce how many moles of oxygen and how many moles of glucose? | Answer: 6 carbon dioxide to 6 oxygen to 1 glucose, so 12 moles of carbon dioxide give 12 moles of oxygen and 2 moles of glucose. |
| 6 | To make 9 g of glucose (molar mass 180), how many moles of carbon dioxide are needed, and what mass is that (molar mass 44)? | Answer: 9 / 180 = 0.05 mol glucose, needing 0.3 mol carbon dioxide, that is 0.3 x 44 = 13.2 g. |
| 7 | Aerobic respiration yields up to 38 ATP per glucose molecule, anaerobic only 2. How many times more is the aerobic yield? | Answer: 38 / 2 = 19 times, because anaerobic respiration does not break glucose down completely. |
| 8 | A leaf of total area 50 square centimetres loses 0.4 cubic centimetres of water per square centimetre per hour. How much water is lost in 8 hours of sunlight? | Answer: 50 x 0.4 = 20.0 cubic centimetres per hour, so 160.0 cubic centimetres in 8 hours. |
Genetics and Molecular Biology
These questions cover monohybrid and dihybrid ratios, DNA base composition, and the genetic code.
| # | Question | Answer and marking notes |
|---|---|---|
| 9 | Two pea plants of genotype Aa are crossed, giving 400 offspring. How many are expected to show the dominant and the recessive phenotype? | Answer: the ratio is 3 to 1, so about 300 dominant and 100 recessive out of 400. |
| 10 | Two individuals of genotype AaBb are crossed, giving 640 offspring. With a 9 to 3 to 3 to 1 ratio, how many show each phenotype? | Answer: 360, 120, 120 and 40, totalling 640. |
| 11 | In a double-stranded DNA sample adenine is 30 per cent. What percentage is thymine, guanine and cytosine? | Answer: thymine 30 per cent; the remaining 40 per cent is shared equally by guanine and cytosine, 20 per cent each. |
| 12 | A messenger RNA has 90 bases used for coding. With 3 bases per amino acid, how many amino acids are translated? | Answer: 90 / 3 = 30 amino acids. |
Energy Flow in Ecosystems
These questions cover energy pyramids, net primary production, population growth and the role of decomposers.
| # | Question | Answer and marking notes |
|---|---|---|
| 13 | Producers fix 50000 kJ. If only one tenth passes to the next trophic level, how much energy reaches the third-level consumer? | Answer: 5000 kJ, then 500 kJ, and 50 kJ at the third level. |
| 14 | An ecosystem has gross primary production of 20000 kJ and plant respiration of 8000 kJ. What is net primary production, and what do primary consumers get at one tenth efficiency? | Answer: net primary production is 12000 kJ, so primary consumers get 1200 kJ. |
| 15 | An island deer population is 500 and grows by one fifth each year. With no immigration or emigration, roughly how many after 2 years? | Answer: 500 x 1.2 to the power 2 = 720 deer. |
| 16 | State two roles of decomposers in the carbon cycle, and the effect on nutrient cycling if decomposers decline sharply. | Answer: decomposers break down organic carbon in dead bodies and waste into carbon dioxide for producers, and release nitrogen and phosphorus back to the soil. A sharp decline leaves organic matter accumulating and inorganic nutrients short, lowering productivity. |
Human Physiology and Coordination
These questions cover cardiac output, kidney filtration, blood glucose and nerve conduction speed.
| # | Question | Answer and marking notes |
|---|---|---|
| 17 | With a heart rate of 70 beats per minute and a stroke volume of 70 mL, what is the cardiac output in mL per minute, and in litres per minute? | Answer: 70 x 70 = 4900 mL per minute, that is 4.9 litres per minute. |
| 18 | Glomerular filtration rate is 125 mL per minute. How many litres are filtered in a full day of 1440 minutes? | Answer: 125 x 1440 = 180000 mL, that is 180.0 litres. |
| 19 | Blood glucose is 5.5 mmol per litre and plasma volume is 3 litres. What is the total amount of glucose in mmol? | Answer: 5.5 x 3 = 16.5 mmol. |
| 20 | A nerve impulse travels at 120 metres per second over 1.2 metres. How long does it take in seconds, and in milliseconds? | Answer: 1.2 / 120 = 0.01 s, that is 10.0 ms. |
Biotechnology and Conservation
These questions cover PCR amplification, gel electrophoresis, reserve planning and yield comparison.
| # | Question | Answer and marking notes |
|---|---|---|
| 21 | Each PCR cycle doubles the number of target DNA fragments. Starting from a single copy, how many copies are present after 30 cycles? | Answer: 2 to the power 30 = 1073741824 copies. |
| 22 | In gel electrophoresis three fragments are 800, 400 and 200 base pairs long. Roughly how many times further does the shortest travel than the longest, and why? | Answer: 800 / 200 = 4 times; shorter fragments meet less resistance in the gel mesh and move faster. |
| 23 | A reserve covers 2000 hectares, with the core zone taking 35 per cent. What is the core area in hectares? | Answer: 2000 x 35 / 100 = 700 hectares. |
| 24 | A genetically modified variety yields 6.5 tonnes per hectare against 5.8 tonnes for the traditional one. Over 10 hectares, what is the difference in total yield and the percentage gain? | Answer: 65.0 tonnes against 58.0, a difference of 7.0 tonnes, or a gain of 12.1 per cent. |
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