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IB Maths AA: Probability and Expectation – Tutor Lesson Plan (independence, conditional probability, variance)

IB Maths AA: Probability and Expectation – Tutor Lesson Plan (independence, conditional probability, variance)

  • 2026-11-05

Students know that independent events multiply, so when a question says given B occurred they multiply anyway. One value of 0.21 carries three different questions here.

Objectives — the student can decide when multiplication is allowed, compute a conditional probability as the intersection over the given event, and get the mean and variance from a probability table.

01 Prerequisites (3-minute check)

If any of these fails, fix it before the lesson starts.

Skill Quick check Pass mark
Multiplying decimals What is 0.4 times 0.7? 0.28
Fraction to decimal What is 21 divided by 70? 0.3
Averages The mean of 0, 1, 2 and 3 1.5

02 Lesson flow (60 minutes)

Time Stage Tutor does Student does
0-8 min Three question types Both, given, and expected value State how they differ
8-20 min Independent events P(A) 0.4, P(B) 0.7 Get 0.28
20-34 min Conditional probability P(A and B) 0.21, P(B) 0.7 Get 0.3
34-48 min Expectation probabilities 0.2, 0.3, 0.4, 0.1 over 0 to 3 Get 1.4
48-56 min Variance E(X squared) minus E(X) squared Get 0.84
56-60 min Exit check Three questions marked Finish alone

03 Teaching script (read it out)

Scene 1: Multiply only after independence is established

For independent A and B, P(A and B) = 0.4 times 0.7 = 0.28.
Worked the other way: a question that gives P(A and B) = 0.21 while P(A)P(B) = 0.28 has already shown the events are not independent.

Student judges what the gap between 0.21 and 0.28 means (the events are linked).

Scene 2: Conditional probability changes the denominator

P(A given B) = P(A and B) divided by P(B) = 0.21 divided by 0.7 = 0.3.
The usual slip is dividing by 0.4. The denominator is always the event that is known to have happened, not the one being asked about.

Student explains why the denominator is 0.7.

Scene 3: Expectation and variance from one table

E(X) = 0(0.2) + 1(0.3) + 2(0.4) + 3(0.1) = 1.4.
E(X squared) = 0 + 0.3 + 1.6 + 0.9 = 2.8, so Var = 2.8 – 1.96 = 0.84.

Note: variance is not E(X squared); the square of the mean must be subtracted.

04 Question types and worked steps

Type Example Steps Answer
Independent events P(A) 0.4, P(B) 0.7 Multiply directly 0.28
Conditional probability P(A and B) 0.21, P(B) 0.7 Intersection over the given event 0.3
Expectation table over 0 to 3 Sum of x times P(x) 1.4
Variance E(X squared) 2.8, E(X) 1.4 E(X squared) minus E(X) squared 0.84
Sanity check (teach this): The probabilities must sum to 1 (here 0.2 + 0.3 + 0.4 + 0.1). If they do not, a row is missing and the expectation is already wrong.

05 Independent practice (3 questions)

Question Answer What to watch
Probability of both, independent 0.28 Independence checked first
Value of P(A given B) 0.3 Denominator is 0.7, not 0.4
Mean and variance mean 1.4, variance 0.84 The mean squared was subtracted

06 Common mistakes and what to say

Mistake Student writes Say this
Wrong denominator answer of 0.525 The denominator is the event known to have happened.
Multiplying dependent events answer of 0.28 The question already gives 0.21, so 0.28 contradicts it.
Variance left as E(X squared) variance of 2.8 Variance equals E(X squared) minus the mean squared.
Probabilities not summing to 1 table totals 0.9 Check the total before computing anything.

07 Homework (paper, section and question numbers)

08 Exit check (last 5 minutes)

Question Answer Decision
P(A and B) when independent 0.28 All three right: move to the normal distribution
P(A given B) 0.3 One wrong: re-teach conditional probability
Mean and variance 1.4 and 0.84 Two wrong: repeat scene 3

09 Tutor FAQ

Are probability formulas in the booklet?

Some are, but the definition of conditional probability must be reproduced.

Variance or standard deviation?

The standard deviation is the square root, in the same units as the data.

Memorise the table method?

No, but always check that the probabilities sum to 1.

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