P2 Maths Money Paper 2: Intermediate
Decimal amounts, repeated buying and change in shopping situations.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: P2 Maths: Money and Change |
| Level | P2 |
| # | Answer | One-line note |
|---|---|---|
| 1 | $75.20 | $48.50 + $26.70 = $75.20, so the total is $75.20. |
| 2 | $62.40 | $100 − $37.60 = $62.40, so the change is $62.40. |
| 3 | $37.50 | $12.50 × 3 = $37.50, so 3 workbooks cost $37.50. |
| 4 | $12.20 | $18.90 × 2 = $37.80, and $50 − $37.80 = $12.20. |
| 5 | $34 | $6.80 × 5 = $34, so 5 packets cost $34. |
| 6 | $30 | $9.90 + $12.30 + $7.80 = $30, so the total is $30. |
| 7 | $6.40 | $5 × 7 = $35, and $35 − $28.60 = $6.40. |
| 8 | 305 cents | $1 = 100 cents, and $3.05 × 100 = 305, so 305 cents. |
| 9 | Exactly enough, no change | $24.90 + $15.10 = $40.00, so $40 is exactly enough. |
| 10 | $36.55 | $60 − $23.45 = $36.55 when the decimals are lined up and borrowed in turn, not $37.55. |
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