P2 Maths Money Paper 3: Challenge
Multi-step shopping, repeated borrowing and missing amounts.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: P2 Maths: Money and Change |
| Level | P2 |
| # | Answer | One-line note |
|---|---|---|
| 1 | $26.60 | $7.80 × 3 = $23.40, and $50 − $23.40 = $26.60. |
| 2 | $61.25 | $200 − $138.75 = $61.25, so the change is $61.25. |
| 3 | $35 | $16.25 × 4 = $65, and $100 − $65 = $35. |
| 4 | $26.20 | $5.50 × 2 + $12.80 = $23.80, and $50 − $23.80 = $26.20. |
| 5 | 876 coins | 10 cents is $0.10, and $87.60 ÷ $0.10 = 876, so 876 coins. |
| 6 | $8.60 | $13.80 × 3 = $41.40, and $50 − $41.40 = $8.60. |
| 7 | $72.30 | $45.60 − $18.90 = $26.70, and $45.60 + $26.70 = $72.30. |
| 8 | $41.50 | $9.75 × 6 = $58.50, and $100 − $58.50 = $41.50. |
| 9 | $7 | $3.50 × 30 = $105, and $105 − $98 = $7. |
| 10 | $53.10 | $80 − $26.90 = $53.10 after borrowing in both the units and the cents, not $54.10. |
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