P4 Maths Perimeter and Area Applications Paper 1: Basics
Ten original items, each with an answer and a one-line explanation.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 15 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: P4 Maths Perimeter and Area Applications |
| Level | P4 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 28 cm | Perimeter = (length + width) times 2 = (9 + 5) times 2 = 28 cm. |
| 2 | 64 cm² | Area = side times side = 8 times 8 = 64 cm². |
| 3 | 84 m² | Area = length times width = 12 times 7 = 84 m². |
| 4 | Length 9 cm, perimeter 30 cm | Length = area divided by width = 54 divided by 6 = 9 cm, and perimeter = 30 cm. |
| 5 | Side 8 cm, area 64 cm² | Side = 32 divided by 4 = 8 cm, so area = 64 cm². |
| 6 | 30000 cm² | One square metre is 10 000 cm², so 3 m² = 30000 cm². |
| 7 | 48 m | Going round the edge means the perimeter: (15 + 9) times 2 = 48 m. |
| 8 | 24 tiles | The floor area is 6 times 4 = 24 m², so 24 tiles of 1 m² are needed. |
| 9 | 75 cm² | The largest square has side 15 cm and area 225 cm², so 300 minus 225 = 75 cm² remains. |
| 10 | The perimeter was given as the area; area 40 cm², perimeter 28 cm | 10 + 4 + 10 + 4 = 28 cm is the perimeter measured in cm; the area is 10 times 4 = 40 cm². |
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