P4 Maths Perimeter and Area Applications Paper 2: Intermediate
Ten original items, each with an answer and a one-line explanation.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: P4 Maths Perimeter and Area Applications |
| Level | P4 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 144 cm² | Area = 12 times 12 = 144 cm², while 12 times 4 = 48 cm is the perimeter. |
| 2 | Width 10 cm, area 150 cm² | Length plus width = 25 cm, so width = 10 cm and area = 150 cm². |
| 3 | 68 m² | The large rectangle is 80 m² and the corner is 12 m², leaving 68 m². |
| 4 | $2400 | The area is 20 m², so the cost is 20 times 120 = $2400. |
| 5 | $2700 | The perimeter is 60 m, so the cost is 60 times 45 = $2700. |
| 6 | 2.5 m² | 10 000 cm² make 1 m², so 25 000 divided by 10 000 = 2.5 m². |
| 7 | 28 cm | The side is 7 cm because 7 times 7 = 49, so the perimeter is 28 cm. |
| 8 | Perimeter 36 cm, area 72 cm² | The rectangle is 12 cm by 6 cm, so its perimeter is 36 cm and its area is 72 cm². |
| 9 | 36 cm² | The wire is the perimeter, so the side is 6 cm and the area is 36 cm². |
| 10 | No, for example 9 cm by 4 cm also has area 36 cm² | The factor pairs of 36 include 1×36, 2×18, 3×12, 4×9 and 6×6; only 6 by 6 is a square. |
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