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P5 Maths Area and Perimeter Paper 3: Challenge

P5 Maths Area and Perimeter Paper 3: Challenge

  • 2026-11-09

P5 Maths Area and Perimeter Paper 3: Challenge

Ten original items, each with an answer and a one-line explanation.

Direct answers Items 1-3 are basic, 4-6 intermediate and 7-9 challenge, with item 10 as the error review. Time yourself first, then check every answer and redo the wrong ones.

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 20
Difficulty mix Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1
Chapter Chapter: P5 Maths Area and Perimeter
Level P5

02 Questions (10 items)

  1. FoundationHow many whole-number rectangles have an area of 36 sq cm, and what is the smallest perimeter?
  2. FoundationAmong rectangles with perimeter 36 cm, what is the greatest possible area?
  3. FoundationA 4 cm by 5 cm rectangle is cut from a corner of a 12 cm by 9 cm rectangle. Find the area and perimeter left.
  4. IntermediateA staircase shape has 3 steps, each 3 cm wide and 2 cm high. Find its area and perimeter.
  5. IntermediateAn L-shaped flower bed is a 10 m square with a 6 m square corner removed. Find its area and the fence needed.
  6. IntermediateA corridor is 20 m long and 1.5 m wide. Carpet costs 85 dollars per sq m. Find the total cost.
  7. ChallengeA square side grows from 7 cm to 10 cm. By how many sq cm does the area increase?
  8. ChallengeA rectangle has perimeter 50 cm and length 15 cm. If the length loses 3 cm and the width gains 3 cm, by how many sq cm does the area increase?
  9. ChallengeA 2 cm square is cut from each corner of a 9 cm square card. Find the area and perimeter left.
  10. Error redoError review: a pupil says two 6 cm by 4 cm rectangles joined into a rectangle always have perimeter 32 cm. What perimeters are possible?

03 Answers and one-line notes

# Answer One-line note
1 5 shapes, smallest perimeter 24 cm 36 = 1 x 36 = 2 x 18 = 3 x 12 = 4 x 9 = 6 x 6, five shapes; the square 6 x 6 gives the smallest perimeter, 24 cm.
2 81 sq cm Length + width = 18 cm, and the product is largest when they are closest, 9 x 9 = 81 sq cm.
3 area 88 sq cm, perimeter 42 cm Area 108 – 20 = 88 sq cm; a corner cut leaves the perimeter unchanged at (12 + 9) x 2 = 42 cm.
4 area 18 sq cm, perimeter 30 cm Area = three 3 x 2 rectangles = 18 sq cm; the perimeter equals the bounding rectangle, 9 cm by 6 cm, so (9 + 6) x 2 = 30 cm.
5 area 64 sq m, fence 40 m Area 100 – 36 = 64 sq m; the notch does not change the outline, so the fence is 10 x 4 = 40 m.
6 2550 dollars The area is 20 x 1.5 = 30 sq m, so the cost is 30 x 85 = 2550 dollars.
7 51 sq cm 10 x 10 – 7 x 7 = 100 – 49 = 51 sq cm; a 3 cm longer side does not add 3 sq cm.
8 6 sq cm more The width is 25 – 15 = 10 cm and the area is 150 sq cm; the new 12 cm by 13 cm shape keeps the perimeter but has area 156 sq cm, which is 6 sq cm more.
9 area 65 sq cm, perimeter 36 cm Area 81 – 4 x 4 = 65 sq cm; eight 2 cm edges go and eight come, so the perimeter stays 36 cm.
10 32 cm or 28 cm The area is always 48 sq cm; joined along the long side the shape is 12 x 4 with perimeter 32 cm, joined along the short side it is 6 x 8 with perimeter 28 cm.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

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