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Displacement Method for Volume Paper 1: Basics

Displacement Method for Volume Paper 1: Basics

  • 2026-11-11

Displacement Method for Volume Paper 1: Basics

Start with the idea of displacement, differences in level and base areas, then unit conversions.

Direct answers Answers and explanations for all ten questions

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 20
Difficulty mix Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1
Chapter Chapter: P5 Displacement Method for Volume
Level P1

02 Questions (10 items)

  1. FoundationA stone is lowered into a measuring cylinder holding 50 mL of water and the level rises to 75 mL. What is the volume of the stone?
  2. FoundationThe base area of a tank is 20 cm squared and the water rises 3 cm after an iron block is put in. Find the volume of the block.
  3. FoundationHow many cm cubed are there in 40 mL?
  4. IntermediateA cylinder holds 120 mL of water and reads 155 mL after a shell is added. Find the volume of the shell.
  5. IntermediateA rectangular tank is 30 cm long and 10 cm wide, and the water rises 2 cm when a stone is placed inside. Find the volume of the stone.
  6. IntermediateHow many cm cubed are there in 2.5 L?
  7. ChallengeAn iron ball of volume 80 cm cubed is put into a cylinder holding 200 mL of water. What will the reading be?
  8. ChallengeWhy is the displacement method used to measure the volume of an irregular object?
  9. ChallengeThe base area of a container is 45 cm squared and the water level goes from 6 cm to 10 cm. Find the volume of the object.
  10. Error redoA student reads 130 mL as the final level and answers that the stone is 130 cm cubed. The cylinder started with 100 mL. What is the correct volume?

03 Answers and one-line notes

# Answer One-line note
1 25 cm cubed, because the level rose by 75 minus 50, and 1 mL is the same as 1 cm cubed. Read the difference in level, not the final reading.
2 60 cm cubed, since base area times rise gives 20 times 3. With a fixed base area, volume equals base area times the rise.
3 40 cm cubed, because 1 mL occupies the same space as 1 cm cubed. Millilitres and cubic centimetres are two names for the same volume.
4 35 cm cubed, since 155 minus 120 is the water pushed aside. Subtract the starting amount first to get the water displaced.
5 600 cm cubed, from a base area of 300 cm squared multiplied by a 2 cm rise. Find the base area first, then multiply by the rise.
6 2500 cm cubed, because 1 L is 1 000 cm cubed. To change litres into cubic centimetres, always multiply by 1 000.
7 280 mL, since the ball sinks fully and pushes aside 80 mL. A fully sunk object displaces water equal to its own volume.
8 An irregular shape has no simple length times width times height, but the water it pushes aside equals its own volume, so the rise in level gives the volume. Displacement turns a hard shape into an easy reading.
9 180 cm cubed, because the rise is 4 cm and 45 times 4 gives the volume. Use the rise, not the final depth.
10 30 cm cubed. The student forgot to subtract the original 100 mL, so the reading is not the volume. The error is treating the final reading as the displaced water.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

Write the two readings, subtract, then multiply by the base area.Tutor Registration →

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