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Displacement Method for Volume Paper 2: Intermediate
Displacement Method for Volume Paper 2: Intermediate
Work backwards to a rise or a base area, then handle overflow and several objects.
Direct answers Answers and explanations for all ten questions
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: P5 Displacement Method for Volume |
| Level | P1 |
02 Questions (10 items)
- FoundationA cylinder holds 80 mL of water and reads 110 mL after a metal block is added. Find the volume of the block.
- FoundationA tank is 25 cm long and 12 cm wide and the water rises 1.5 cm. Find the volume of the object.
- FoundationA stone of volume 600 cm cubed is put into a tank with base area 200 cm squared. How far does the water rise?
- IntermediateA stone of volume 45 cm cubed is placed in 50 mL of water. What is the new reading?
- IntermediateA basin full to the brim holds 500 mL. A stone of 120 cm cubed is put in. How much water overflows?
- IntermediateThree identical steel balls are put into 60 mL of water and the reading rises to 96 mL. Find the volume of one ball.
- Challenge1.2 L of water is poured into a box with base area 400 cm squared. How deep is the water?
- ChallengeAn object of volume 750 cm cubed makes the water rise 2.5 cm. What is the base area of the tank?
- ChallengeA container holds 300 mL. After the first object the reading is 350 mL, and after a second object it is 420 mL. Find the volume of the second object.
- Error redoThe water in a tank of base area 150 cm squared rises 2 cm. A student answers 150 cm cubed. What is the correct volume?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 30 cm cubed, from 110 minus 80. | The difference in readings is the water displaced. |
| 2 | 450.0 cm cubed, from a base area of 300 cm squared times 1.5. | Multiply a decimal rise directly; do not round it off. |
| 3 | 3.0 cm, because 600 divided by 200 gives the rise. | When the volume is known, divide to find the rise. |
| 4 | 95 mL, from 50 plus 45. | When the volume is known, add to find the reading. |
| 5 | 120 mL, because the water is already full, so all the displaced water spills out. | When the container is full, displaced water equals the overflow. |
| 6 | 12 cm cubed, since the three share 36 mL and 36 divided by 3 gives one ball. | Find the total first, then divide by the number of pieces. |
| 7 | 3.0 cm, because 1.2 L is 1 200 cm cubed and 1 200 divided by 400 gives the depth. | Change litres into cm cubed first, then divide by the base area. |
| 8 | 300.0 cm squared, from 750 divided by 2.5. | Volume divided by the rise gives the base area. |
| 9 | 70 cm cubed, since 420 minus 350 gives the second object. | Subtract the reading before and after each addition. |
| 10 | 300 cm cubed. The student forgot to multiply by the rise; 150 times 2 is the volume. | The base area is only one factor of the volume. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
Decide whether the volume, the rise or the base area is wanted, then multiply or divide.Tutor Registration →
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