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Displacement Method for Volume Paper 4: Error Clinic

Displacement Method for Volume Paper 4: Error Clinic

  • 2026-11-11

Displacement Method for Volume Paper 4: Error Clinic

Ten real slips taken apart, from reading-as-volume to zero for a floating block.

Direct answers Answers and explanations for all ten questions

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 20
Difficulty mix Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1
Chapter Chapter: P5 Displacement Method for Volume
Level P1

02 Questions (10 items)

  1. FoundationA cylinder starts at 100 mL and reads 150 mL after a stone is added. A student answers 150 cm cubed. What is correct?
  2. FoundationThe level goes from 75 mL to 115 mL and a student answers 115 cm cubed. What is the correct volume?
  3. FoundationA rectangular base is 20 cm by 5 cm and the water rises 3 cm. A student uses the perimeter 50 cm times 3 and answers 150 cm cubed. What is correct?
  4. IntermediateA student writes that 1 L is 100 cm cubed, so 3 L is 300 cm cubed. What is the correct answer?
  5. IntermediateFour identical beads raise the level from 40 mL to 100 mL and a student answers 60 cm cubed each. What is correct?
  6. IntermediateA container full to the brim holds 1 500 mL and 180 mL overflows when a stone is added. A student answers 1 500 cm cubed. What is correct?
  7. ChallengeA tank of base area 60 cm squared shows a rise of 2.5 cm and a student answers 60 cm cubed. What is the correct volume?
  8. ChallengeA wooden block floats and the level hardly moves, so a student answers that its volume is zero. What is wrong?
  9. ChallengeThe depth rises from 5 cm to 6.2 cm in a tank of base area 200 cm squared. A student multiplies 6.2 by 200 and answers 1 240 cm cubed. What is correct?
  10. Error redoTwo objects of 90 cm cubed each are put into water and a student counts only one and answers 90 cm cubed. How much water do both displace?

03 Answers and one-line notes

# Answer One-line note
1 50 cm cubed. The 150 is the final reading, so the original 100 mL must be subtracted. Error: taking the reading as the volume. Fix: subtract the starting amount.
2 40 cm cubed, using the rise of 40 rather than the final reading. Error: the subtraction was skipped. Fix: always write final minus starting reading.
3 300 cm cubed, since the base area is 100 cm squared and 100 times 3 gives the volume. Error: the perimeter was used as an area. Fix: multiply only length by width.
4 3000 cm cubed, because 1 L is 1 000 cm cubed and 3 times 1 000 is the answer. Error: the litre conversion lost a zero. Fix: 1 L is 1 000 cm cubed.
5 15 cm cubed, because the four share 60 mL and 60 divided by 4 gives one bead. Error: the division by the number of pieces was missed.
6 180 cm cubed. The overflow is the volume of the stone; the capacity of the container is irrelevant. Error: the capacity was taken as the volume. Fix: read only the overflow.
7 150.0 cm cubed, from 60 times 2.5. Error: the rise was not multiplied in. Fix: base area times rise.
8 The block only floats, so it is not fully submerged and displaces less than its own volume. Press it under with a needle or tie on a weight, then measure the rise. Error: assuming no rise means no volume. Fix: make the floating body sink fully.
9 240.00000000000003 cm cubed. The rise is 1.2 cm, and 1 240 would be the water plus the object. Error: the depth was used instead of the rise. Fix: subtract the original depth.
10 180 cm cubed, from 90 times 2. Error: the second object was left out. Fix: add each piece or multiply by the count.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

Name the faulty step, give the correct method, then check with the readings.Tutor Registration →

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