P6 Maths Composite Shapes Paper 3: Challenge
- 2026-11-09
P6 Maths Composite Shapes Paper 3: Challenge
Ten original items, each with an answer and a one-line explanation.
Direct answers Items 1-3 are basic, 4-6 intermediate and 7-9 challenge, with item 10 as the error review. Time yourself first, then check every answer and redo the wrong ones.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: P6 Maths Composite Shapes with Circles |
| Level | P6 |
02 Questions (10 items)
- FoundationFind the area of a semicircle of radius 10 cm. (Take pi = 3.14)
- FoundationFind the area of a quarter circle of radius 8 cm.
- FoundationA semicircle has diameter 14 cm. Find its perimeter, including the diameter.
- IntermediateA ring has outer radius 15 cm and inner radius 9 cm. Find its area.
- IntermediateA square has side 20 cm and contains its largest inscribed circle. Find the area outside the circle.
- IntermediateFind the perimeter of a quarter circle of radius 7 cm.
- ChallengeA rectangle is 18 cm by 8 cm and a semicircle is joined to one long side, using that side as its diameter. Find the total area.
- ChallengeA ring has area 263.76 cm² and inner radius 4 cm. Find the outer radius.
- ChallengeA running track is a 40 m rectangle with a semicircle at each end; both semicircles have diameter 20 m. Find the length of one lap.
- Error redoError review: a pupil finds the area of a ring with radii 15 cm and 9 cm as 3.14 × (15 − 9) × (15 − 9) = 113.04 cm². What is the correct area?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 157 cm² | 3.14 × 10 × 10 ÷ 2 = 157 cm². |
| 2 | 50.24 cm² | 3.14 × 64 ÷ 4 = 50.24 cm². |
| 3 | 35.98 cm | The arc is 3.14 × 14 ÷ 2 = 21.98 cm, and adding the 14 cm diameter gives 35.98 cm. |
| 4 | 452.16 cm² | 3.14 × (225 − 81) = 3.14 × 144 = 452.16 cm². |
| 5 | 86 cm² | The square is 400 cm² and the circle is 314 cm², so 86 cm² remains. |
| 6 | 24.99 cm | The arc is 2 × 3.14 × 7 ÷ 4 = 10.99 cm, and two radii add 14 cm, giving 24.99 cm. |
| 7 | 271.17 cm² | The rectangle is 144 cm² and the semicircle is 127.17 cm², giving 271.17 cm² in total. |
| 8 | 10 cm | 263.76 ÷ 3.14 = 84, and 84 + 16 = 100, so the outer radius is 10 cm. |
| 9 | 142.8 m | The two straight sides give 2 × 40 = 80 m, and the arcs make one circle of 3.14 × 20 = 62.8 m, so one lap is 142.8 m. |
| 10 | 452.16 cm² | Square first, then subtract: 3.14 × (225 − 81) = 452.16 cm². Subtracting the radii before squaring loses area. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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