P6 Maths Composite Shapes Paper 4: Error Review
Ten original items, each with an answer and a one-line explanation.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: P6 Maths Composite Shapes with Circles |
| Level | P6 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 127.17 cm² | The radius is 9 cm, so 3.14 × 81 ÷ 2 = 127.17 cm². |
| 2 | 78.5 cm² | 3.14 × 100 ÷ 4 = 78.5 cm². |
| 3 | 15.42 cm | 3.14 × 6 ÷ 2 = 9.42 cm, and adding 6 cm gives 15.42 cm. |
| 4 | 172.7 cm² | 3.14 × (64 − 9) = 3.14 × 55 = 172.7 cm². |
| 5 | 42.14 cm² | 196 − 3.14 × 49 = 196 − 153.86 = 42.14 cm². |
| 6 | 21.42 cm | The arc is 2 × 3.14 × 6 ÷ 4 = 9.42 cm, and two radii add 12 cm, giving 21.42 cm. |
| 7 | 160.14 cm² | 3.14 × (100 − 49) = 3.14 × 51 = 160.14 cm². |
| 8 | 3925 dollars | The area is 3.14 × 100 ÷ 2 = 157 m², and multiplying by 25 gives 3925 dollars. |
| 9 | 27.52 cm² | Each circle has diameter 8 cm and radius 4 cm, so together they take 100.48 cm² and 27.52 cm² remains. |
| 10 | 41.12 cm | Halve the circle first, then add the diameter: 3.14 × 16 ÷ 2 + 16 = 41.12 cm. |
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