P6 Maths Discount, Profit and Loss Paper 3: Challenge
Ten original items, each with an answer and a one-line explanation.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: P6 Maths Discount, Profit and Loss |
| Level | P6 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 912 dollars | 1200 × 0.8 × 0.95 = 912 dollars. |
| 2 | 20% | (540 − 450) ÷ 450 × 100% = 20%. |
| 3 | 585 dollars | 450 × 1.3 = 585 dollars. |
| 4 | 560 dollars | Cost = 644 ÷ 1.15 = 560 dollars. |
| 5 | 324 dollars | The sale price must be 270 × 1.08 = 291.6 dollars, so the marked price is 291.6 ÷ 0.9 = 324 dollars. |
| 6 | 16% | The price is 700 × 0.6 = 420 dollars, a loss of 80 dollars, so 80 ÷ 500 × 100% = 16%. |
| 7 | 960 dollars | 960 × 1.25 × 0.8 = 960 dollars, which is exactly the original marked price. |
| 8 | a loss of 40 dollars | Takings are 960 dollars against a cost of 1000 dollars, so the loss is 40 dollars. |
| 9 | 480 dollars | The sale price must be 384 dollars, so the marked price is 384 ÷ 0.8 = 480 dollars. |
| 10 | 20% | The marked price is 300 dollars and it sells for 240 dollars, a profit of 40, so 40 ÷ 200 × 100% = 20%. |
Book a Maths tutorTutor Registration →
Questions and answers are written originally by the TutorZone team and are not taken from any school, publisher or examination authority paper. Every value is checked by computer.

