P6 maths ratio and proportion paper 1 (basics): simplifying and missing terms
Ten items to build the basics: writing and simplifying ratios, matching units, sharing in a ratio and finding a missing term.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: P6 Maths Ratio and Proportion |
| Level | P6 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 4 : 1 | Write 12 : 3, divide both terms by 3 to get 4 : 1, meaning 4 sweets for each pupil. |
| 2 | 3 : 4 | The highest common factor of 18 and 24 is 6, and dividing both terms by 6 gives 3 : 4. |
| 3 | 5 : 8 | Divide 35 and 56 by 7 to get 5 : 8, and 5 and 8 share no further factor. |
| 4 | 4 : 1 | Use the same unit first: 2 m = 200 cm, then 200 : 50 divides by 50 to give 4 : 1. |
| 5 | 9 : 15 | Multiplying both terms by the same non-zero number keeps the value, so 3 : 5 = 9 : 15. |
| 6 | 4 : 5 | Divide 16 : 20 by 4 to get 4 : 5, that is 4 boys for every 5 girls. |
| 7 | 35 beads and 10 beads | There are 7 + 2 = 9 parts, 45 ÷ 9 = 5 beads per part, so 7 × 5 = 35 and 2 × 5 = 10. |
| 8 | x = 21 | The first term is multiplied by 3 to reach 12, so the second term is 7 × 3 = 21. |
| 9 | 2 : 3 : 5 | B is 3 in both ratios, so the parts already match and the three terms join as 2 : 3 : 5. |
| 10 | 2 : 3 | Multiplying both terms by 10 only clears the decimals; 6 : 9 still divides by 3, so 0.6 : 0.9 = 2 : 3. |
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