P6 maths ratio and proportion paper 2 (intermediate): sharing and scale
Ten intermediate items: decimal and fraction ratios, three-part sharing, missing terms, map scale and school totals.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: P6 Maths Ratio and Proportion |
| Level | P6 |
| # | Answer | One-line note |
|---|---|---|
| 1 | A gets $90 and B gets $150 | There are 8 parts, 240 ÷ 8 = 30 dollars per part, so A gets 3 × 30 = 90 and B gets 5 × 30 = 150. |
| 2 | 3 : 5 | Multiply both terms by 10 to get 15 : 25, then divide by 5 to reach 3 : 5. |
| 3 | 6 : 5 | Multiply both terms by 8: 3/4 × 8 = 6 and 5/8 × 8 = 5, giving 6 : 5. |
| 4 | 105 g | 2 parts weigh 30 g, so 1 part is 15 g and the water is 7 × 15 = 105 g, giving 135 g of solution in all. |
| 5 | 18, 27 and 36 | There are 9 parts, 81 ÷ 9 = 9 per part, so the parts are 18, 27 and 36. |
| 6 | x = 10 | Cross-multiply: 12x = 8 × 15 = 120, so x = 10. |
| 7 | 800 m | The real length is 4 × 20000 = 80000 cm, which is 800 m after dividing by 100. |
| 8 | 300 boys and 240 girls | There are 9 parts, 540 ÷ 9 = 60 pupils per part, so 5 × 60 = 300 boys and 4 × 60 = 240 girls. |
| 9 | $120, $150 and $180 | There are 15 parts, 450 ÷ 15 = 30 dollars per part, giving 120, 150 and 180 dollars. |
| 10 | A gets $180 and B gets $240 | Add the parts first: 3 + 4 = 7, then 420 ÷ 7 = 60 per part and multiply by 3 and 4; dividing by 4 is not the number of parts. |
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