Primary General Studies: Transport and Communication in Hong Kong (Paper 4 (error clinic))
Paper four re-drills the most common errors from the first three papers, with different numbers throughout.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: Primary General Studies: Transport and Communication in Hong Kong |
| Level | parts of a closed circuit, conductors against insulators, series against parallel, adding up battery voltage, and electrical safety |
| # | Answer | One-line note |
|---|---|---|
| 1 | Six departures. | Sixty minutes gives 5 gaps, and counting both ends makes 6 departures. |
| 2 | $117.6. | 9.8 times 2 trips and then 6 days gives 117.6. |
| 3 | 32 km/h. | Dividing 8 by 0.25 is the same as multiplying by 4. |
| 4 | 27 minutes. | Add the three parts: 5 plus 16 plus 6 gives 27 minutes. |
| 5 | $8.8. | Multiply 22 by 4 and then place the decimal point one place from the right. |
| 6 | 72 km/h. | Multiply by 3.6, so 20 becomes 72 km/h. |
| 7 | 12.5 MB each. | Half of 25 is 12.5, and both emails stay within the limit. |
| 8 | 1 350 g. | The gap per kilometre is 90 g, and 15 km gives 1 350 g. |
| 9 | At 8:20 a.m. | Six stations give 5 gaps of 2 minutes, so 8:10 plus 10 minutes is 8:20. |
| 10 | The end departures were missed, so the answer is 6. | Both the 7:00 and 8:00 departures count, and 5 gaps give 6 departures. |
With all four done, go back to the chapter page and revise the three parts of a closed circuit plus three safety habits.Tutor Registration →
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