P4 Maths: The Relationship between Multiplication and Division (Paper 3 (challenge))
Paper 3 (challenge): ten questions on the inverse link between multiplication and division, two divisions from one fact, checking with multiplication, remainders, and missing factors or dividends, with answers and one-line notes.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: P4 Maths: The Relationship between Multiplication and Division |
| Level | P4 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 12. | 96 / 8 = 12, checked by 8 x 12 = 96. |
| 2 | 12. | 144 / 12 = 12, so both factors happen to be equal. |
| 3 | 7 x 14 + 2 = 100. | Add the remainder back; a remainder of 2 is valid because it is smaller than the divisor 7. |
| 4 | 76. | Dividend = divisor x quotient + remainder = 9 x 8 + 4. |
| 5 | 72 / 8 = 9. | First find the number with 6 x 12 = 72, then divide it by 8. |
| 6 | 3. | Division reverses multiplication, so the quotient is simply the other factor, 3. |
| 7 | 4. | 5 x 8 = 40, 8 x 5 = 40, 40 / 5 = 8 and 40 / 8 = 5 give four sentences in all. |
| 8 | 9 + 12 = 21. | First find the other factor with 108 / 9 = 12, then add; asking for the sum instead of the product is the usual trap. |
| 9 | 80. | 720 is ten times 72, so the quotient is ten times 8, which is 80. |
| 10 | No. You cannot divide by zero. | Division by zero is undefined; only 0 / 5 = 0 is valid. |
Check the answers; for a wrong item write divisor x quotient + remainder and see whether it equals the dividend.Tutor Registration →
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