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P6 Maths: Simple Interest (Paper 3 (challenge))
Tutor Prep Guide · The simple-interest formula I = P x R x T, substituting principal and annual rate, converting months to years, finding P, R or T from the interest, and the amount A = P + I
P6 Maths: Simple Interest (Paper 3 (challenge))
Paper 3 (challenge): ten simple-interest questions with answers and one-line notes.
Direct answers Level: P6 maths; format: the simple-interest formula, months as years, finding P or R, and the amount.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: P6 Maths: Simple Interest |
| Level | P6 |
02 Questions (10 items)
- FoundationPrincipal $6000 at 4% per year for 1.5 years. Find the simple interest.
- FoundationBank A pays 4% on $5000 for 2 years; Bank B pays 4.5% on $4500 for 2 years. Which pays more interest, and by how much?
- FoundationThe simple interest is $252 on $2800 for 1.5 years. Find the annual rate.
- IntermediateA sum at 6% per year for 2 years amounts to $1120. Find the principal.
- ChallengePrincipal $3000 at 5% per year is withdrawn after 8 months. Find the simple interest.
- Challenge$10000 is split into two parts at 4% and 6% per year, earning $520 in one year. How much is the 4% part?
- ChallengePrincipal $12000 at 3% per year for 3 months. Find the simple interest.
- IntermediateA sum at 5% per year for 2 years amounts to $1320. Find the principal and the interest.
- IntermediateCompare the interest on $2000 for 1 year at 6% with $1000 for 2 years at 6%. Which is more?
- Error redo(Error clinic) Keung charged 5% on $1000 for 2 years by using 1050 as the principal in year two, getting 102.5. What went wrong, and what is the simple interest?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | $360 | 1.5 years gives 6000 x 0.04 x 1.5 = 360. |
| 2 | Bank B, by $5 | A gives 400 and B gives 405, a difference of 5. |
| 3 | 6% | R = 252 x 100 / (2800 x 1.5) = 6. |
| 4 | $1000 | The amount is 1.12 times the principal, so 1120 / 1.12 = 1000. |
| 5 | $100 | 8 months is 8/12 year, so 3000 x 0.05 x 8/12 = 100. |
| 6 | $4000 | If the 4% part is x, then 0.04x + 0.06(10000 – x) = 520, giving x = 4000. |
| 7 | $90 | 3 months is 0.25 year, so 12000 x 0.03 x 0.25 = 90. |
| 8 | Principal $1200, interest $120 | Divide 1320 by 1.1 to get 1200, and the interest is 1320 – 1200 = 120. |
| 9 | They are equal, both $120 | 2000 x 0.06 x 1 = 120 and 1000 x 0.06 x 2 = 120. |
| 10 | He computed compound interest; simple interest is $50 each year, $100 in total | Simple interest always uses the original $1000, so 1000 x 0.05 x 2 = 100. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
Check the answers, copy the working of any wrong item, then try another paper of this chapter.Tutor Registration →
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