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P6 Maths Speed, Distance and Time Paper 3: Challenge

P6 Maths Speed, Distance and Time Paper 3: Challenge

  • 2026-11-09

P6 Maths Speed, Distance and Time Paper 3: Challenge

Ten original items, each with an answer and a one-line explanation.

Direct answers Items 1-3 are basic, 4-6 intermediate and 7-9 challenge, with item 10 as the error review. Time yourself first, then check every answer and redo the wrong ones.

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 20
Difficulty mix Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1
Chapter Chapter: P6 Maths Speed, Distance and Time
Level P6

02 Questions (10 items)

  1. FoundationA 240 m train clears a 360 m bridge in 40 s. Find its speed in m/s and km/h.
  2. FoundationA lorry runs 120 km at 80 km/h then 90 km at 60 km/h. Find the average speed.
  3. FoundationThree legs: 30 km at 60 km/h, 60 km at 120 km/h and 90 km at 90 km/h. Find the average speed.
  4. IntermediateA walks at 60 m/min and leaves 5 minutes early; B walks at 80 m/min from the same point. When does B catch up?
  5. IntermediateA hill is climbed at 3 km/h and descended by the same route at 6 km/h. Find the average speed.
  6. IntermediateA 150 m train clears an 850 m tunnel in 20 s. Find its speed in m/s and km/h.
  7. ChallengeA 240 km trip is planned at 60 km/h, but the driver leaves 40 minutes late. What speed keeps the planned arrival time?
  8. ChallengeTwo towns are 60 km apart. A leaves at 12 km/h and B at 8 km/h towards each other. When and where do they meet?
  9. ChallengeConvert 108 km/h to m/s, then find the time to cover 900 m.
  10. Error redoError review: a 120 m train at 15 m/s crosses a 300 m bridge; a pupil says 20 s. What is correct?

03 Answers and one-line notes

# Answer One-line note
1 15 m/s, which is 54 km/h It must cover 240 + 360 = 600 m, so 600 / 40 = 15 m/s and x 3.6 gives 54 km/h.
2 70 km/h The legs take 1.5 h and 1.5 h, so 210 km over 3 h gives 70.
3 90 km/h The times add to 0.5 + 0.5 + 1 = 2 h for 180 km, so 180 / 2 = 90.
4 15 minutes A leads by 60 x 5 = 300 m and B gains 20 m a minute, so 300 / 20 = 15.
5 4 km/h With equal distances the average is 2 x 3 x 6 / (3 + 6) = 4, since the descent takes only a third of the time.
6 50 m/s, which is 180 km/h It covers 150 + 850 = 1000 m, so 1000 / 20 = 50 m/s and x 3.6 gives 180 km/h.
7 72 km/h Only 3 h 20 min (10/3 h) remain, so 240 / (10/3) = 72.
8 3 hours, 36 km from A They close at 20 km/h, so 60 / 20 = 3 h, and A covers 12 x 3 = 36 km.
9 30 m/s, 30 seconds 108 / 3.6 = 30 m/s, and 900 / 30 = 30 s.
10 28 seconds The train must cover bridge plus its own length: 420 / 15 = 28 s; 20 s only covers the bridge.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

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