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S1 Maths: Angles and Parallel Lines, Paper 3 (Challenge)

S1 Maths: Angles and Parallel Lines, Paper 3 (Challenge)

  • 2026-11-09

S1 Maths: Angles and Parallel Lines, Paper 3 (Challenge)

Ten challenge items mixing angle ratios, two-step equations and all three parallel-line angle relations, with full answers and explanations.

Can one figure contain several angle relations? Yes. A single figure often mixes vertically opposite, corresponding and co-interior angles, so each angle must be judged separately.

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 25
Difficulty mix Foundation 3 · Intermediate 2 · Challenge 4 · Error redo 1
Chapter Chapter: S1 Maths: Angles and Parallel Lines
Level Level: Challenge

02 Questions (10 items)

  1. FoundationThree angles meet at a point and are in the ratio 2 : 3 : 4. Find the three angles.
  2. FoundationTwo parallel lines are cut by a transversal. A pair of co-interior angles is 3x − 20 and 2x + 30. Find x and the angles.
  3. IntermediateTwo lines intersect. A pair of vertically opposite angles is 7x − 5 and 4x + 40. Find the angle and its supplement.
  4. IntermediateTwo parallel lines are cut by a transversal. A pair of co-interior angles is 2x + 15 and 3x + 35. Find x and the angles.
  5. FoundationFour angles meet at a point: 85°, 95°, 110° and x. Find x.
  6. ChallengeAn angle and its supplement are in the ratio 5 : 7. Find the two angles.
  7. ChallengeA transversal cuts two parallel lines. A pair of alternate angles is 4x + 10 and 6x − 30. Find the angle and its co-interior angle.
  8. ChallengeThree angles 2x + 20, 3x − 10 and 60° lie on a straight line. Find x and the angles.
  9. ChallengeA transversal cuts two parallel lines and one angle is 118°. Find its alternate angle, its co-interior angle and the difference.
  10. Error redoA student treats corresponding angles as supplementary. Given one corresponding angle of 132°, find the other and give the correct reason.

03 Answers and one-line notes

# Answer One-line note
1 The angles are 80°, 120° and 160° Divide 360° into 9 equal parts of 40°.
2 x = 34, the angles are 82° and 98° Solve 5x + 10 = 180 because co-interior angles are supplementary.
3 The angle is 100° and its supplement is 80° Use 7x − 5 = 4x + 40 to get x = 15, then take the supplement.
4 x = 26, the angles are 67° and 113° Solve 5x + 50 = 180 because co-interior angles are supplementary.
5 x = 70° Angles at a point add up to 360°.
6 The angles are 75° and 105° The two angles add up to 180°; split it in the ratio 5 : 7.
7 The angle is 90° and its co-interior angle is 90° Alternate angles give x = 20 and an angle of 90°, so the co-interior angle is also 90°.
8 x = 22, the angles are 64°, 56° and 60° Adjacent angles on a straight line add up to 180, so 5x + 70 = 180.
9 Alternate angle 118°, co-interior angle 62°, difference 56° The alternate angle is equal and the co-interior angle is supplementary, so they differ by 56°.
10 The other is 132°; corresponding angles are equal Corresponding angles are equal; it is co-interior angles that add up to 180.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

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