S1 Maths: Ratio, Rate and Proportion (Paper 1 (basics))
Paper 1 (basics): ten questions on simplifying ratios, missing terms, sharing in a ratio, direct and inverse proportion, speed conversion and average speed, with answers and one-line notes.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S1 Maths: Ratio, Rate and Proportion |
| Level | S1 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 2 : 3. | Divide both terms by the highest common factor 6 to get 2 : 3. |
| 2 | 3 : 4. | Divide both terms by 15 to get 3 : 4. |
| 3 | 12. | The second term grows from 5 to 20, that is times 4, so the first term is 12. |
| 4 | 60 km/h. | Speed equals distance divided by time, so 120 divided by 2 is 60 km/h. |
| 5 | 15 dollars each. | Unit price is total cost divided by quantity, so 90 divided by 6 is 15. |
| 6 | 3. | 20 divided by 4 is 5, so x is 15 divided by 5, which is 3. |
| 7 | 14 and 49. | There are 9 parts in total, each part is 7, so the shares are 14 and 49. |
| 8 | 40 m. | Distance is speed times time, so 8 times 5 is 40 metres. |
| 9 | 1 : 3. | Multiply both terms by 2 to get 1 : 3; a decimal ratio can be turned into whole numbers first. |
| 10 | 2 : 3. | Divide both terms by 4 to get 2 : 3; the answer 4 : 6 is not yet in simplest form. |
Check the answers; find the highest common factor when reducing, and fix the total for inverse proportion.Tutor Registration →
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