S2 Maths Pythagoras Theorem Paper 1: Basics
Find the hypotenuse from two legs, and a missing leg from the hypotenuse.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S2 Maths: Pythagoras Theorem |
| Level | S2 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 5 cm | 3² + 4² = 25, so the hypotenuse is √25 = 5 cm. |
| 2 | 10 cm | 36 + 64 = 100, so the hypotenuse is 10 cm. |
| 3 | 13 m | 25 + 144 = 169, so the hypotenuse is 13 m. |
| 4 | 12 cm | 169 − 25 = 144, so the other leg is 12 cm. |
| 5 | 24 cm | 625 − 49 = 576, so the other leg is 24 cm. |
| 6 | 17 cm | 64 + 225 = 289, so the hypotenuse is 17 cm. |
| 7 | 8.49 cm | 36 + 36 = 72, and √72 = 8.49 cm. |
| 8 | 15 cm | 81 + 144 = 225, so the hypotenuse is 15 cm. |
| 9 | Yes | 49 + 576 = 625, which equals 25², so it is right-angled. |
| 10 | 5 cm | The hypotenuse is not the sum of the legs; add the squares, then take the root. |
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