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S2 Maths: Simultaneous Linear Equations (Foundation, 10 Questions)

S2 Maths: Simultaneous Linear Equations (Foundation, 10 Questions)

  • 2026-11-08

S2 Maths: Simultaneous Linear Equations (Foundation, 10 Questions)

A foundation set on the two entry methods for a pair of linear equations in two unknowns: add or subtract when the coefficients match, or substitute when one equation already gives y in terms of x. All ten answers are integers, each with a one-line note.

Quick answer Answers in order: (7, 3), (7, 5), (3, 5), (3, 6), (4, 2), (3, 4), (4, 1), (3, 2), (2, 3), and 13 with 7.

01 Paper details (check answers afterwards)

Item Detail
Questions 10 questions
Suggested time about 25 minutes
Difficulty mix Foundation 10
Chapter Chapter: S2 Maths: Simultaneous Linear Equations
Level S2

02 Questions (10 items)

  1. FoundationSolve the simultaneous equations x + y = 10 and x – y = 4.
  2. FoundationSolve x + y = 12 and x – y = 2.
  3. FoundationSolve 2x + y = 11 with x = 3.
  4. FoundationSolve y = 2x and x + y = 9.
  5. FoundationSolve 3x + 2y = 16 with y = 2.
  6. FoundationSolve 2x + y = 10 and x + 2y = 11.
  7. FoundationSolve x – y = 3 and 2x + y = 9.
  8. FoundationSolve 2x + 3y = 12 and 2x + y = 8.
  9. FoundationSolve 5x + 2y = 16 and 3x + 2y = 12.
  10. FoundationTwo numbers add up to 20 and differ by 6. Find them.

03 Answers and one-line notes

# Answer One-line note
1 x = 7, y = 3 Adding the two equations gives 2x = 14, so x = 7, and y = 3 follows from x + y = 10.
2 x = 7, y = 5 Adding gives 2x = 14 so x = 7, and subtracting gives 2y = 10 so y = 5.
3 x = 3, y = 5 Put x = 3 into the first equation: 6 + y = 11, so y = 5.
4 x = 3, y = 6 Substituting y = 2x gives x + 2x = 9, so x = 3 and y = 6.
5 x = 4, y = 2 Putting y = 2 gives 3x + 4 = 16, so 3x = 12 and x = 4.
6 x = 3, y = 4 Doubling the first equation gives 4x + 2y = 20; subtracting the second leaves 3x = 9, so x = 3 and y = 4.
7 x = 4, y = 1 Adding the equations gives 3x = 12, so x = 4 and y = 1 follows from x – y = 3.
8 x = 3, y = 2 Subtracting removes x and leaves 2y = 4, so y = 2 and then 2x + 2 = 8 gives x = 3.
9 x = 2, y = 3 Subtracting gives 2x = 4 so x = 2, and 10 + 2y = 16 then gives y = 3.
10 13 and 7 Let the numbers be x and y with x + y = 20 and x – y = 6; adding gives 2x = 26, so x = 13 and y = 7.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

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