S2 Maths: Simultaneous Linear Equations (Foundation, 10 Questions)
A foundation set on the two entry methods for a pair of linear equations in two unknowns: add or subtract when the coefficients match, or substitute when one equation already gives y in terms of x. All ten answers are integers, each with a one-line note.
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | about 25 minutes |
| Difficulty mix | Foundation 10 |
| Chapter | Chapter: S2 Maths: Simultaneous Linear Equations |
| Level | S2 |
| # | Answer | One-line note |
|---|---|---|
| 1 | x = 7, y = 3 | Adding the two equations gives 2x = 14, so x = 7, and y = 3 follows from x + y = 10. |
| 2 | x = 7, y = 5 | Adding gives 2x = 14 so x = 7, and subtracting gives 2y = 10 so y = 5. |
| 3 | x = 3, y = 5 | Put x = 3 into the first equation: 6 + y = 11, so y = 5. |
| 4 | x = 3, y = 6 | Substituting y = 2x gives x + 2x = 9, so x = 3 and y = 6. |
| 5 | x = 4, y = 2 | Putting y = 2 gives 3x + 4 = 16, so 3x = 12 and x = 4. |
| 6 | x = 3, y = 4 | Doubling the first equation gives 4x + 2y = 20; subtracting the second leaves 3x = 9, so x = 3 and y = 4. |
| 7 | x = 4, y = 1 | Adding the equations gives 3x = 12, so x = 4 and y = 1 follows from x – y = 3. |
| 8 | x = 3, y = 2 | Subtracting removes x and leaves 2y = 4, so y = 2 and then 2x + 2 = 8 gives x = 3. |
| 9 | x = 2, y = 3 | Subtracting gives 2x = 4 so x = 2, and 10 + 2y = 16 then gives y = 3. |
| 10 | 13 and 7 | Let the numbers be x and y with x + y = 20 and x – y = 6; adding gives 2x = 26, so x = 13 and y = 7. |
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