S2 Maths: Simultaneous Linear Equations (Challenge, 10 Questions)
The challenge paper asks students to decide whether a system has one solution, none or infinitely many, to clear fractional coefficients and to build equations from context, all with answers and full reasoning.
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | about 35 minutes |
| Difficulty mix | Challenge 10 |
| Chapter | Chapter: S2 Maths: Simultaneous Linear Equations |
| Level | S2 |
| # | Answer | One-line note |
|---|---|---|
| 1 | x = 4, y = 3 | Adding gives 8x = 32 so x = 4, and 16 + 5y = 31 then gives y = 3. |
| 2 | x = 6, y = 6 | Multiplying both by 6 gives 3x + 2y = 30 and 2x + 3y = 30; subtracting leaves x – y = 0, so x = y = 6. |
| 3 | length 11 cm, width 6 cm | With l + w = 17 from the perimeter and l – w = 5, adding gives l = 11 and w = 6. |
| 4 | A 6 kg, B 4 kg | Let A be a kg: 60a + 80(10 – a) = 680, giving 20a = 120, so A is 6 kg and B is 4 kg. |
| 5 | infinitely many | The second equation is twice the first, so both describe the same line and every point on it satisfies both equations. |
| 6 | none | The left sides are identical but the right sides differ, so no pair can satisfy both; the two lines are parallel. |
| 7 | x = 3, y = -2 | The second equation gives y = 3x – 11; substituting leaves 7x – 22 = -1, so x = 3 and y = -2. |
| 8 | 47 | With tens digit t and units u: t + u = 11 and u – t = 3, so t = 4 and u = 7, giving 47. |
| 9 | 16 years | With t years to come: 40 + t = 2(12 + t), so t = 16. |
| 10 | x = 5, y = 2 | Subtracting removes y and gives 4x = 20, so x = 5 and 15 + 4y = 23 gives y = 2. |
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