S2 Maths Simultaneous Equations Paper 4: Error Review
Ten original error-review items, each with an answer and a one-line explanation.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S2 Maths Simultaneous Equations |
| Level | S2 |
| # | Answer | One-line note |
|---|---|---|
| 1 | x = 6, y = 4 | Adding gives 2x = 12 so x = 6, and substitution gives y = 4; x = 8 uses only one equation. |
| 2 | x = 4, y = 3 | Adding gives 2x = 8 so x = 4, then y = 3 by substitution. |
| 3 | x = 4, y = 5 | 2x = 8 gives x = 4, then x + y = 9 gives y = 5. |
| 4 | y = 3 | Substituting gives 6 + 2y = 12, so 2y = 6 and y = 3; missing the halving gives 6. |
| 5 | x = 4, y = 2 | Substitute x = 2y to get 2y + 2y = 8, so y = 2 and x = 4. |
| 6 | x = 3, y = 5 | Substituting gives 3x + 2 = 11, so x = 3 and y = 5. |
| 7 | x = 4, y = 2 | Subtracting the equations removes y and gives x = 4; then 8 + 2y = 12 gives y = 2. |
| 8 | x = 3, y = 2 | Adding removes y: 8x = 24 so x = 3; then 9 + 2y = 13 gives y = 2. |
| 9 | 7 two-dollar and 5 five-dollar stamps | With x + y = 12 and 2x + 5y = 39, subtracting twice the first from the second gives 3y = 15, so y = 5 and x = 7. |
| 10 | x = 6, y = 2 | Adding gives 2x = 12 so x = 6 and y = 2; 4 and 4 satisfy only the first equation, giving 0 instead of 4 in the second. |
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