S2 Science: Combustion, Oxidation and Mass (Paper 3 (challenge))
- 2026-11-14
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S2 Science: Combustion, Oxidation and Mass (Paper 3 (challenge))
This paper centres on conservation of mass and practices word equations, exothermic reactions and putting out oil fires, then uses fixed mass ratios to calculate carbon dioxide, sulphur dioxide, water and the composition of rust.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S2 Science: Combustion, Oxidation and Mass |
| Level | S2 |
02 Questions (10 items)
- FoundationWrite the word equation for the complete combustion of carbon.
- FoundationIs burning exothermic or endothermic?
- FoundationWhy does sand put out a burning oil fire?
- IntermediateWhat mass of carbon dioxide forms when 12 g of carbon reacts completely with 32 g of oxygen?
- IntermediateWhat is the mass ratio of magnesium to oxygen in magnesium oxide?
- IntermediateWhy does the number of atoms not change in a chemical reaction?
- ChallengeHow much sulphur dioxide forms when 8 g of sulphur burns completely?
- ChallengeHow much water forms when 4 g of hydrogen burns completely?
- ChallengeA 20 g sample of rust contains 6 g of oxygen. What mass of iron is present and what percentage is oxygen?
- Error redoIt is said that 4 g of hydrogen and 4 g of oxygen react completely. What is wrong?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | Carbon + oxygen -> carbon dioxide | Reactants go on the left of the arrow and products on the right, with ignition as the condition. |
| 2 | Exothermic, since burning gives out heat and light | That is why burning can cook food and generate electricity, turning chemical energy into heat and light. |
| 3 | The sand cuts off oxygen from the air, so the flame dies for lack of oxygen | Oil floats on water and would splash, so sand is used rather than water. |
| 4 | 44 g | By conservation of mass, 12 plus 32 equals 44, so the total mass of reactants equals that of products. |
| 5 | 24 to 16, that is 3 to 2 | This fixed ratio lets you work out the mass of magnesium oxide from the mass of magnesium. |
| 6 | Atoms are only rearranged, never destroyed or created | Because the atoms are unchanged in number, the total mass is unchanged, which is conservation of mass. |
| 7 | 16 g | Sulphur and sulphur dioxide are in the ratio 32 to 64, so 8 g of sulphur takes 8 g of oxygen to give 16 g. |
| 8 | 36 g | Hydrogen, oxygen and water are in the mass ratio 4 to 32 to 36, so 4 g of hydrogen needs 32 g of oxygen. |
| 9 | 14 g of iron, and oxygen is 30 percent | Subtract 6 from 20 for the iron, and 6 divided by 20 times 100 gives the oxygen percentage. |
| 10 | Hydrogen and oxygen react in the ratio 4 to 32, so 4 g of oxygen can burn only 0.5 g of hydrogen and hydrogen is left over | The mass ratio of reactants is fixed, so equal masses do not both get used up. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
For combustion and oxidation questions ask three things: whether the question is about conditions, observations or mass, how many reactants and products there are, and which gas entering or leaving explains any change in mass.Tutor Registration →
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