S3 Maths: Central Tendency and Data Display (Paper 1: basics)
S3 maths central tendency paper one, basics: ten questions from mean, median and mode to pie chart angles.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S3 Maths: Central Tendency and Data Display |
| Level | S3 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 8 | The total 40 divided by five values gives 8. |
| 2 | 9 | With seven values sorted, the fourth one in the middle is 9. |
| 3 | 7 | Seven appears three times, more often than any other value. |
| 4 | 6.75 | The total 27 divided by four values gives 6.75. |
| 5 | 3.5 | With six values, average the middle pair 3 and 4 to get 3.5. |
| 6 | 2 100 | The total equals the mean times the count, 70 times 30 gives 2 100. |
| 7 | 12 | The total 60 minus the sum 48 leaves 12. |
| 8 | 90 degrees | 360 degrees times 25 percent gives 90 degrees. |
| 9 | 12 | The old total 40 plus 20 gives 60, divided by five values makes 12. |
| 10 | No, there can be several modes or none | Two values can tie for most frequent, and if every value appears once there is no mode. |
Add all values then divide by the count for the mean, always sort before finding the median, trust the median when extreme values appear, and weight by group size when combining two groups.Tutor Registration →
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