S3 Maths: Central Tendency and Data Display (Paper 2: intermediate)
S3 maths central tendency paper two, intermediate: ten questions from frequency table means and weighted means to midpoint estimates.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S3 Maths: Central Tendency and Data Display |
| Level | S3 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 1.9 | The total 4 plus 6 plus 9 is 19, divided by ten students gives 1.9. |
| 2 | 11.5 | With twelve values, average the sixth and seventh, 11 and 12, to get 11.5. |
| 3 | 22 | The largest 31 minus the smallest 9 gives 22. |
| 4 | 67 | The weighted total 160 plus 210 plus 300 is 670, divided by the total weight 10 gives 67. |
| 5 | 14 | The new total 54 minus the old total 40 gives 14. |
| 6 | 26.5 | With six values, average the middle pair 25 and 28 to get 26.5. |
| 7 | 50.5 | The midpoints 44.5 and 54.5 weighted by 8 and 12 give 50.5. |
| 8 | 2 790 | 62 times 45 gives 2 790. |
| 9 | 7.8 | The total 39 divided by five gives 7.8, while the median is 7. |
| 10 | The median should be used instead, since the mean is dragged away | An extreme value pulls the mean up or down, while the median depends only on position. |
Add all values then divide by the count for the mean, always sort before finding the median, trust the median when extreme values appear, and weight by group size when combining two groups.Tutor Registration →
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