S3 Maths: Central Tendency and Data Display (Paper 4: mistake clinic)
S3 maths central tendency paper four, mistake clinic: ten questions fixing mean and median confusion, unsorted data and weighting errors.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S3 Maths: Central Tendency and Data Display |
| Level | S3 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 8 | The total 40 divided by five gives 8; mean and median are different measures. |
| 2 | 4 | Four appears twice, more often than any other value. |
| 3 | 120 | The mean times the count gives the total, 15 times 8 is 120. |
| 4 | 4 | With seven values there is a single middle position, the fourth value. |
| 5 | 38 | The largest 45 minus the smallest 7 gives 38. |
| 6 | 65 | The weighted total 80 plus 180 is 260, divided by four gives 65. |
| 7 | 73.3 | The total 1 400 minus 300 leaves 1 100, divided by fifteen gives 73.3. |
| 8 | 9 | With four values, average the middle pair 8 and 10 to get 9. |
| 9 | 324 degrees | 360 times 0.9 gives 324 degrees. |
| 10 | The data must be sorted first, an unsorted middle value is not the median | The median is defined by position after sorting, so an unsorted middle value can be anything. |
Add all values then divide by the count for the mean, always sort before finding the median, trust the median when extreme values appear, and weight by group size when combining two groups.Tutor Registration →
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