S3 Maths: Linear Inequalities in One Unknown (Paper 2: intermediate)
This second paper concentrates on negative signs and brackets, where most errors happen. Whenever you divide by a negative number, write a small reminder to reverse the sign.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S3 Maths: Linear Inequalities in One Unknown |
| Level | S3 Maths |
| # | Answer | One-line note |
|---|---|---|
| 1 | x < -4 | Divide both sides by -2; dividing by a negative number reverses the sign and 8 / (-2) = -4. |
| 2 | x >= -4 | Divide by -3, which turns <= into >=, and 12 / (-3) = -4. |
| 3 | x <= 4 | Expand to 2x + 6 <= 14, subtract 6, then divide by 2 to get 4. |
| 4 | x > 5 | Expand to 3x – 6 > 9, add 6, then divide by 3 to get 5. |
| 5 | x < 6 | Subtract 1 to get x / 2 < 3, then multiply by 2 to get 6. |
| 6 | x <= 3 | Rearrange to -x >= -3, and multiplying by -1 reverses the sign to x <= 3. |
| 7 | x < 4 | Subtract 2x to get 2x + 1 < 9, subtract 1, then divide by 2 to get 4. |
| 8 | x < 3 | Rearrange to -2x > -6, then divide by -2 and reverse the sign to get x < 3. |
| 9 | 4 | The solution is x < 4.5, and the greatest integer below 4.5 is 4. |
| 10 | The correct answer is x <= -4 | Dividing by -5 reverses the sign, so >= must become <=. |
The intermediate trap is a negative number: multiplying or dividing by a negative number reverses the inequality sign. Remove brackets first, clear fractions by multiplying by the denominator, then substitute a value to check.Tutor Registration →
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