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S3 Science: Forces, Motion, Speed-Time Graphs and Net Force (Paper 2: intermediate)

S3 Science: Forces, Motion, Speed-Time Graphs and Net Force (Paper 2: intermediate)

  • 2026-11-13

S3 Science: Forces, Motion, Speed-Time Graphs and Net Force (Paper 2: intermediate)

The second paper connects formula, graph and friction, focusing on average speed and the direction of net force.

Direct answers Write the knowns and the unknown before choosing a formula, which removes many slips.

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 20
Difficulty mix Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1
Chapter Chapter: S3 Science: Forces, Motion, Speed-Time Graphs and Net Force
Level S3 Science

02 Questions (10 items)

  1. FoundationWhat is divided by what to get average speed?
  2. FoundationWhat is the average speed when 240 metres take 40 seconds?
  3. FoundationTwo forces of 20 N and 12 N act in the same direction. What is the net force?
  4. IntermediateTwo forces of 20 N and 12 N act in opposite directions. What is the net force?
  5. IntermediateA 2 kg object feels a net force of 6 N. What is its acceleration?
  6. IntermediateWhat net force gives a 10 kg object an acceleration of 2 m/s²?
  7. ChallengeA 4 kg box is pushed with 20 N against 8 N of friction. What is its acceleration?
  8. ChallengeAn object moves at constant velocity under a 15 N push. What is the friction?
  9. ChallengeStarting from rest, an object reaches 20 m/s in 5 seconds. What is its acceleration?
  10. Error redoA student turns a 10 N net force on 2 kg into 20 m/s². What is the correct answer?

03 Answers and one-line notes

# Answer One-line note
1 Total distance divided by total time When the pace changes you cannot average the speeds, so use the whole distance over the whole time.
2 6 m/s Dividing 240 by 40 gives 6 in metres per second.
3 32 N Forces in the same direction add, so 20 plus 12 gives 32 newtons.
4 8 N in the direction of the 20 N force Opposite forces subtract and the net force follows the larger one.
5 3 m/s² Rearranging F = ma gives a as 6 divided by 2, which is 3.
6 20 N Using F = ma, 10 times 2 is 20 newtons.
7 3 m/s² The net force is 20 minus 8, and dividing 12 by the mass of 4 gives 3.
8 15 N Constant velocity means zero net force, so friction must equal the push and point the other way.
9 4 m/s² Acceleration is the change in speed over time, so 20 divided by 5 is 4.
10 5 m/s² In F = ma the force is divided by the mass, so 10 over 2 is 5.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

The intermediate step links formula and graph: average speed is total distance over total time, F = ma handles net force and acceleration, and friction always opposes relative motion.Tutor Registration →

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