Secondary Biology: Inheritance and Mendel (Paper 4)
- 2026-10-31
Secondary Biology: Inheritance and Mendel (Paper 4)
Ten original questions splitting 960 Tt×Tt seeds into 240, 480 and 240, counting the tall class, working a tt×tt cross, handling the 9/16 double dominant class, the AB chance from IAi×IBi, and the children of a colour-blind father and a homozygous normal mother.
Direct answer Write the parental genotypes first, then use 1:2:1 for genotypes and 3:1 for phenotypes.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: Secondary Biology: Inheritance and Mendel |
| Level | 4 basic, 3 advanced, 2 challenge and 1 redo question |
02 Questions (10 items)
- FoundationIn 960 seeds from a Tt×Tt cross, how many are expected to be homozygous tall TT?
- FoundationIn the same 960 seeds, how many are expected to be short?
- FoundationHow many chromosomes does a gamete produced by meiosis carry?
- FoundationWhat phenotypes appear in the offspring of a tt×tt cross?
- IntermediateHow many of the 960 seeds from Tt×Tt are tall?
- IntermediateWhat is the genotype ratio TT:Tt:tt among Tt×Tt offspring, and what numbers does it give out of 960 seeds?
- IntermediateTwo independently inherited traits each follow a 3:1 ratio. Out of 640 offspring, how many show both dominant traits?
- ChallengeParents with blood groups IAi and IBi have a child. What is the chance the child is AB?
- ChallengeA colour-blind father (XᶜY) has children with a homozygous normal mother (XX). What about the daughters and the sons?
- Error redoKnowing that Tt×Tt gives 3:1, a student says 720 of the 960 seeds are short. What is the correct number?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 240 seeds, the pure-breeding tall quarter. | The offspring genotypes come in a 1:2:1 ratio, so a quarter of the total is each homozygous class. |
| 2 | 240 seeds, since tt is one quarter of the offspring. | Shortness is recessive and shows only in tt, which is one quarter of the offspring. |
| 3 | Twenty-three, half of the 46 in a body cell. | Meiosis halves the chromosome number so that fertilisation restores the full 46. |
| 4 | All short, that is 100 per cent. | Both parents carry only the recessive allele, so no dominant offspring can appear. |
| 5 | 720 seeds. | The dominant class covers both homozygote and heterozygote, so add the first two parts of 1:2:1. |
| 6 | One to two to one, that is 240, 480 and 240 seeds. | The 3:1 figure is the phenotypic ratio; 1:2:1 is the genotypic ratio and the two must not be mixed up. |
| 7 | 360 offspring, that is 9/16 of 640. | With independent assortment the double dominant class is 9/16, obtained from three quarters times three quarters. |
| 8 | One in four. | Four gamete combinations are possible and only IAIB gives group AB, so the chance is one quarter. |
| 9 | All daughters are carriers but not colour-blind, and all sons are normal. | The father passes his affected X only to daughters; sons receive his Y, so they cannot inherit colour blindness from him. |
| 10 | 240 seeds, because the 3:1 ratio is tall to short. | The error comes from reversing the order of the ratio; state which trait comes first before calculating. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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