S4 Biology Membranes and Transport, Paper 2: water potential and transport rate
Paper 2 follows mass change and diffusion distance through osmosis, active transport and the square law of diffusion time.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S4 Biology: Membranes and Transport |
| Level | S4 |
| # | Answer | One-line note |
|---|---|---|
| 1 | From high to low concentration | Net movement follows the concentration gradient until the two sides even out. |
| 2 | From higher to lower water potential | Water moves from the higher water potential, which is the weaker solution. |
| 3 | Energy in the form of ATP | Active transport can go against the gradient, so it needs energy from respiration. |
| 4 | It swells and bursts | Pure water has the highest water potential, so water floods in and the membrane bursts. |
| 5 | 30 per cent | The gain is 0.6 g, which is 30 per cent of the original 2.0 g. |
| 6 | Towards the 0.3 M solution | The 0.3 M solution has more solute and lower water potential, so water moves into it. |
| 7 | 4 seconds | Distance divided by rate gives 0.2 by 0.05, which is 4 seconds. |
| 8 | Twice as large for the 1 cm cube | The 1 cm cube gives 6 and the 2 cm cube gives 3, so the smaller one is twice as effective. |
| 9 | 32 seconds | Four times the distance needs sixteen times the time, so 2 times 16 gives 32. |
| 10 | It can move substances against the gradient, so ATP is needed | Diffusion follows the gradient, while active transport can go against it and so needs energy. |
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