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S4 ICT: Data Representation and Binary Encoding (Paper 4 (error clinic))

S4 ICT: Data Representation and Binary Encoding (Paper 4 (error clinic))

  • 2026-11-14

S4 ICT: Data Representation and Binary Encoding (Paper 4 (error clinic))

Paper 4 (error clinic): ten data representation questions with answers and one-line notes.

Direct answers Level: S4 ICT; format: number base conversion, bits and bytes, two’s complement, character encoding, image and sound size, compression.

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 20
Difficulty mix Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1
Chapter Chapter: S4 ICT: Data Representation and Binary Encoding
Level S4

02 Questions (10 items)

  1. FoundationHow many bytes are there in 40 bits?
  2. FoundationWhat denary value is the two’s complement pattern 11111111, and why is it not 255?
  3. FoundationWhat denary values do the hex digits A and F stand for, and what is 0xFF?
  4. IntermediateAn 800 by 600 image at 24-bit colour holds how many bits and how many bytes?
  5. IntermediateMono sound at 44.1 kHz and 16 bits uses how many bytes per second?
  6. IntermediateHow many bytes are in 2 MiB?
  7. ChallengeWhat is the denary value of binary 0.11?
  8. ChallengeWhich of JPEG and PNG is lossy, and how do they differ after decompression?
  9. ChallengeBy how much do the ASCII codes of the capital letters D and A differ?
  10. Error redoA student says Unicode is merely a lengthened ASCII, so one Chinese character takes a single byte. What is wrong?

03 Answers and one-line notes

# Answer One-line note
1 5 bytes Converting bits to bytes means dividing by eight.
2 Minus one; 255 only appears if the same bits are read as unsigned The top bit weighs minus 128 and the seven remaining ones bring the total to minus one.
3 A is 10 and F is 15, so 0xFF is 255 Fifteen sixteens plus fifteen gives 255, and two hex digits fill exactly eight bits.
4 11 520 000 bits, which is 1 440 000 bytes 800 times 600 times 24 gives 11 520 000 bits, and dividing by eight gives 1 440 000 bytes.
5 88 200 bytes 44 100 samples times two bytes gives 88 200.
6 2 097 152 bytes One MiB is 1 024 times 1 024 bytes, then doubled.
7 0.75 The first fractional place is one half and the second is one quarter.
8 JPEG is lossy and PNG is lossless, so a lossy file never returns to the exact original Lossy compression discards detail for a smaller file, and repeated saving accumulates the loss.
9 3 Letters sit consecutively in the ASCII table, so 68 minus 65 gives 3.
10 Unicode gives every script a code point, and in UTF-8 a Chinese character usually needs three bytes, while ASCII covers only 128 characters The encoding and the byte count are different questions: one code point is not one byte.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

A computer only knows 0 and 1, so text, images and sound are all encoded into bits first. Keep bits apart from bytes, remember the top bit of a two’s complement number is a negative weight, and compute image or sound size as count times bits per item divided by eight, then check the unit in bytes, KiB or MiB.Tutor Registration →

Questions and answers are written originally by the TutorZone team and are not taken from any school, publisher or examination authority paper. Every value is checked by computer.

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