S4 ICT Data Representation, Paper 1: binary, hexadecimal and units
Paper 1 goes from 1011 giving 11, 45 as 00101101, hex 2F giving 47 and one byte being 8 bits, on to 3 bytes as 24 bits, 2 KiB as 2048 bytes, A to D giving 68, 1011 plus 0110 giving 10001 and 5 MiB as 5242880 bytes.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S4 ICT: Data Representation |
| Level | S4 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 11 | One times 8 plus zero times 4 plus one times 2 plus one times 1 gives 8 plus 2 plus 1, which is 11. |
| 2 | 00101101 | 45 is 32 plus 8 plus 4 plus 1, so the bits from left to right read 00101101. |
| 3 | 47 | Two times 16 is 32 and F stands for 15, so the total is 47. |
| 4 | 8 bits | A byte is always 8 bits, so 8 bytes are 64 bits. |
| 5 | 24 bits | Three times 8 is 24, so three bytes are 24 bits. |
| 6 | 2048 bytes | The binary prefix Ki means 1024, so 2 KiB is 2 times 1024, which is 2048 bytes. |
| 7 | 68 | Each following letter adds one, and A to D is three steps, so 65 plus 3 gives 68. |
| 8 | 10001 | 1011 is 11 and 0110 is 6; 11 plus 6 is 17, which in binary is 10001. |
| 9 | 5242880 bytes | Mi means 1024 times 1024, which is 1048576, and times 5 gives 5242880 bytes. |
| 10 | 4 bits | Hexadecimal has 16 symbols and 2 to the power 4 is 16, so each hex digit holds 4 bits. |
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