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S4 ICT: Network Security and Encryption (Paper 3 (challenge))

S4 ICT: Network Security and Encryption (Paper 3 (challenge))

  • 2026-11-14

S4 ICT: Network Security and Encryption (Paper 3 (challenge))

Paper 3 (challenge): ten network security and encryption questions with answers and one-line notes.

Direct answers Level: S4 ICT; format: Caesar cipher, symmetric and asymmetric encryption, RSA, hashing, digital signatures, TLS and certificates.

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 20
Difficulty mix Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1
Chapter Chapter: S4 ICT: Network Security and Encryption
Level S4

02 Questions (10 items)

  1. FoundationA six-letter password uses only the 26 lowercase letters; what is the key space 26 to the power 6?
  2. FoundationWhat is that key space in bits of entropy, to one decimal place?
  3. FoundationA system has 2 to the power 40 keys and an attacker tries a billion keys per second; what is the average time in seconds?
  4. IntermediateAn RSA key is 4096 bits long; how many bytes is that?
  5. IntermediateTwelve users need 66 symmetric keys but only 24 asymmetric keys; how many keys are saved?
  6. IntermediateMD5 produces 128 bits and SHA-256 produces 256 bits; by how many bytes do they differ?
  7. ChallengeIn a digital signature the sender hashes the message; which key encrypts that hash?
  8. ChallengeIn a TLS session, what do asymmetric and symmetric encryption each do?
  9. ChallengeA certificate runs from 1 January 2026 to 1 January 2027; how many days remain on 15 June 2026?
  10. Error redoA student says an AES-encrypted message must reveal whether anyone tampered with it. What is wrong?

03 Answers and one-line notes

# Answer One-line note
1 308915776 Multiplying 26 by itself six times gives 308915776.
2 28.2 bits The base-two logarithm of 308915776 is about 28.2 bits.
3 About 549.8 seconds Two to the fortieth is about 1.1 trillion keys, half of them on average divided by a billion gives about 549.8 seconds.
4 512 bytes 4096 divided by 8 gives 512 bytes.
5 42 keys 66 minus 24 leaves 42, and the gap widens as users are added.
6 16 bytes The difference of 128 bits is 16 bytes, so SHA-256 output is twice as long.
7 The sender own private key The receiver opens it with the sender public key, which proves origin and integrity.
8 Asymmetric encryption exchanges the session key, and symmetric encryption protects the data afterwards Symmetric ciphers are fast enough for bulk data, while asymmetric ones solve key distribution.
9 200 days From 15 June to the end of the year is 199 days and the first of January adds one more.
10 Encryption only hides content; detecting changes needs a hash or a message authentication code Confidentiality and integrity are separate goals, handled by encryption and hashing respectively.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

Encryption serves three aims: hiding content, proving origin and detecting tampering, and each aim uses a different tool. A Caesar cipher has only 26 keys and falls to brute force or frequency analysis, while modern systems exchange a session key with asymmetric encryption and then send data with fast symmetric encryption, using a hash plus a private key for digital signatures. Count keys, bits and bytes carefully before calculating.Tutor Registration →

Questions and answers are written originally by the TutorZone team and are not taken from any school, publisher or examination authority paper. Every value is checked by computer.

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