S4 Maths indices and logarithms paper 1: index laws and the log definition
Ten items start from the index laws and then bring in fractional indices, negative indices and the definition of a logarithm, each with an answer and a one-line note.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S4 Maths Indices and Logarithms |
| Level | S4 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 128 | For the same base, add the indices: 3 + 4 = 7, so 2^7 = 128. |
| 2 | 729 | A power of a power multiplies the indices: 2 x 3 = 6, giving 3^6 = 729. |
| 3 | 1.2 | Any non-zero number to the power 0 is 1, and 5^-1 = 1/5 = 0.2, so the total is 1.2. |
| 4 | 4 | The denominator 3 means a cube root: 8^(1/3) = 2, then square it to get 4. |
| 5 | 1/8 | A negative index means a reciprocal: 16^(3/4) = 8, so the answer is 1/8. |
| 6 | x = 5 | Write 32 as a power of 2: 32 = 2^5, so comparing indices gives x = 5. |
| 7 | 4.2 x 10^-4 | The point moves four places to the right, so the index is -4 and the form is 4.2 x 10^-4. |
| 8 | 6 | Which power of 2 gives 64? Since 2^6 = 64, the logarithm is 6. |
| 9 | 2 | log base 3 of 81 is 4 and log base 3 of 1/9 is -2, so the sum is 2. |
| 10 | The indices must be added, so the answer is 2^7 = 128 | Multiplying powers of the same base adds the indices rather than multiplying them: 3 + 4 = 7, so 2^7 = 128. |
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