S4 Maths indices and logarithms paper 2: equations and simplification
Ten items move on to exponential equations, combining logarithms of one base, simplifying expressions with negative indices and dividing in scientific notation.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S4 Maths Indices and Logarithms |
| Level | S4 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 9 | 27^(1/3) = 3, and squaring gives 9. |
| 2 | 3 | Since 10^3 = 1000, the logarithm is 3. |
| 3 | 4 | 9^(1/2) = 3 and 4^0 = 1, so the total is 4. |
| 4 | x = 2.5 | Since 81 = 3^4, we have 2x – 1 = 4 and x = 2.5. |
| 5 | x³y³ | Subtract indices for the same base: x gives 5 – 2 = 3 and y gives -2 – (-5) = 3. |
| 6 | 3 | Adding logarithms multiplies the numbers: 8 x 125 = 1000, so the value is 3. |
| 7 | x = 4 | Combining gives x(x – 2) = 8, so x = 4 or -2; the negative root makes the logarithm undefined, leaving 4. |
| 8 | 8 a^6 | 16^(3/4) = 8 and the index of a becomes 8 x 3/4 = 6, giving 8a^6. |
| 9 | 3 x 10^-4 | First 3.6 / 1.2 = 3, then the index is -7 – (-3) = -4, giving 3 x 10^-4. |
| 10 | The logarithms must be added, so log 6 = log 2 + log 3 = 0.7782 | The product law is log(ab) = log a + log b, so 0.3010 + 0.4771 = 0.7782, while multiplying gives only 0.1436. |
Book a Maths tutorTutor Registration →
Questions and answers are written originally by the TutorZone team and are not taken from any school, publisher or examination authority paper. Every value is checked by computer.

