S4 Maths indices and logarithms paper 3: substitution, mixed bases and digit counts
Ten harder items on substitution into a quadratic in the index, combining logarithms of different bases, counting digits and common misconceptions.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S4 Maths Indices and Logarithms |
| Level | S4 |
| # | Answer | One-line note |
|---|---|---|
| 1 | x = -1.5 | Write both sides as powers of 2: 2^(2x) = 2^-3, so 2x = -3 and x = -1.5. |
| 2 | 2 | log base 5 of 125 is 3 and log base 5 of 5 is 1, so the difference is 2. |
| 3 | 2.25 | Take the reciprocal and square: (3/2)^2 = 9/4 = 2.25. |
| 4 | x = 1 | Subtracting logarithms divides the arguments: (x + 2)/x = 3, so x = 1 and both arguments stay positive. |
| 5 | a⁴b³ | Multiply the indices: a becomes 2/3 x 6 = 4 and b becomes 1/2 x 6 = 3, giving a^4 b^3. |
| 6 | 1.7482 | Since 56 = 8 x 7, log 56 = 3 log 2 + log 7 = 0.9030 + 0.8451 = 1.7482. |
| 7 | x = 0 or x = 1 | Let y = 3^x, so y^2 – 4y + 3 = 0 gives y = 1 or 3, hence x = 0 or x = 1. |
| 8 | x = 4 | log base 4 of x is half of log base 2 of x, so 1.5 log base 2 of x = 3 and x = 4. |
| 9 | 31 digits | log(2^100) = 100 x 0.3010 = 30.10, and the digit count is the integer part plus one, so 31 digits. |
| 10 | The index cannot be treated as a divisor; x = log 3 / log 2 = 1.5850 | An unknown in the index needs logarithms: x = log 3 / log 2 = 1.5850, whereas 3/2 merely divides by the base. |
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