S4 Maths: Quadratic Equations and the Discriminant (Paper 3 (challenge))
- 2026-11-15
S4 Maths: Quadratic Equations and the Discriminant (Paper 3 (challenge))
Paper 3 (challenge): ten questions on quadratic equations and the discriminant with answers and one-line notes.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S4 Maths: Quadratic Equations and the Discriminant |
| Level | S4 |
02 Questions (10 items)
- FoundationIf 2x^2 – 5x + k = 0 has real roots, find the range of k.
- FoundationIf x^2 – (m + 1)x + 4 = 0 has a repeated root, find m.
- FoundationSolve 3x^2 + 2x – 1 = 0.
- IntermediateSolve x^2 – 2x – 2 = 0, correct to three decimal places.
- IntermediateThe roots are 3 + sqrt(2) and 3 – sqrt(2). Write down the equation.
- IntermediateThe roots of x^2 + px + 8 = 0 differ by 2. Find the possible values of p.
- ChallengeIf 4x^2 + (k – 2)x + 1 = 0 has a repeated root, find k.
- ChallengeIf alpha and beta are the roots of x^2 – 3x + 1 = 0, find alpha squared plus beta squared.
- ChallengeIf 2x^2 + kx + 8 = 0 has no real roots, find the range of k.
- Error redoError clinic: what does a negative discriminant mean?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | k <= 3.125. | Real roots need 25 – 8k >= 0, so k is at most 25 over 8, that is 3.125. |
| 2 | m = 3 or m = -5. | A zero discriminant gives (m + 1) squared equal to 16, so m + 1 is plus or minus 4. |
| 3 | x = 1/3 or x = -1. | The discriminant is 4 + 12 = 16 with square root 4, giving 1/3 and -1. |
| 4 | x = 2.732 or x = -0.732. | The discriminant is 4 + 8 = 12 with square root about 3.464, so the roots are 1 plus or minus 1.732. |
| 5 | x^2 – 6x + 7 = 0. | The sum is 6 and the product is 9 – 2 = 7, so the equation is x squared minus 6x plus 7. |
| 6 | p = -6 or p = 6. | With product 8 and difference 2 the roots are 2 and 4, or -2 and -4, with sums 6 and -6. |
| 7 | k = 6 or k = -2. | A zero discriminant gives (k – 2) squared equal to 16, so k – 2 is plus or minus 4. |
| 8 | It equals 7. | Using sum 3 and product 1, the sum of squares is 9 – 2 = 7. |
| 9 | -8 < k < 8. | No real root needs k squared below 64, so k lies between -8 and 8. |
| 10 | The equation has no real roots. | A negative discriminant means the curve never meets the x axis, so there is no real root and it is not a repeated root. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
Write down a, b and c first, then work out the discriminant. A positive discriminant gives two distinct real roots, a zero discriminant one repeated root, and a negative one no real root. For a parameter question, form the discriminant in terms of the parameter and then set it positive, zero or negative.Tutor Registration →
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