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S4 Maths: Quadratic Equations and the Discriminant (Paper 3 (challenge))

S4 Maths: Quadratic Equations and the Discriminant (Paper 3 (challenge))

  • 2026-11-15

S4 Maths: Quadratic Equations and the Discriminant (Paper 3 (challenge))

Paper 3 (challenge): ten questions on quadratic equations and the discriminant with answers and one-line notes.

Direct answers Level: S4 maths; format: factorising, the quadratic formula, the discriminant, sum and product of roots.

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 20
Difficulty mix Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1
Chapter Chapter: S4 Maths: Quadratic Equations and the Discriminant
Level S4

02 Questions (10 items)

  1. FoundationIf 2x^2 – 5x + k = 0 has real roots, find the range of k.
  2. FoundationIf x^2 – (m + 1)x + 4 = 0 has a repeated root, find m.
  3. FoundationSolve 3x^2 + 2x – 1 = 0.
  4. IntermediateSolve x^2 – 2x – 2 = 0, correct to three decimal places.
  5. IntermediateThe roots are 3 + sqrt(2) and 3 – sqrt(2). Write down the equation.
  6. IntermediateThe roots of x^2 + px + 8 = 0 differ by 2. Find the possible values of p.
  7. ChallengeIf 4x^2 + (k – 2)x + 1 = 0 has a repeated root, find k.
  8. ChallengeIf alpha and beta are the roots of x^2 – 3x + 1 = 0, find alpha squared plus beta squared.
  9. ChallengeIf 2x^2 + kx + 8 = 0 has no real roots, find the range of k.
  10. Error redoError clinic: what does a negative discriminant mean?

03 Answers and one-line notes

# Answer One-line note
1 k <= 3.125. Real roots need 25 – 8k >= 0, so k is at most 25 over 8, that is 3.125.
2 m = 3 or m = -5. A zero discriminant gives (m + 1) squared equal to 16, so m + 1 is plus or minus 4.
3 x = 1/3 or x = -1. The discriminant is 4 + 12 = 16 with square root 4, giving 1/3 and -1.
4 x = 2.732 or x = -0.732. The discriminant is 4 + 8 = 12 with square root about 3.464, so the roots are 1 plus or minus 1.732.
5 x^2 – 6x + 7 = 0. The sum is 6 and the product is 9 – 2 = 7, so the equation is x squared minus 6x plus 7.
6 p = -6 or p = 6. With product 8 and difference 2 the roots are 2 and 4, or -2 and -4, with sums 6 and -6.
7 k = 6 or k = -2. A zero discriminant gives (k – 2) squared equal to 16, so k – 2 is plus or minus 4.
8 It equals 7. Using sum 3 and product 1, the sum of squares is 9 – 2 = 7.
9 -8 < k < 8. No real root needs k squared below 64, so k lies between -8 and 8.
10 The equation has no real roots. A negative discriminant means the curve never meets the x axis, so there is no real root and it is not a repeated root.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

Write down a, b and c first, then work out the discriminant. A positive discriminant gives two distinct real roots, a zero discriminant one repeated root, and a negative one no real root. For a parameter question, form the discriminant in terms of the parameter and then set it positive, zero or negative.Tutor Registration →

Questions and answers are written originally by the TutorZone team and are not taken from any school, publisher or examination authority paper. Every value is checked by computer.

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