S4 Maths quadratic graphs paper 1: intercepts, discriminant and opening
Ten items start with reading a graph: the y-intercept, the x-intercepts, the sign of the discriminant, the opening direction, and intercepts read straight off a factorisation.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S4 Maths Quadratic Graphs |
| Level | S4 |
| # | Answer | One-line note |
|---|---|---|
| 1 | (0, 3) | Put x = 0 to get y = 3, so the intercept is (0, 3), which is just the constant term. |
| 2 | (2, 0) and (3, 0) | Setting y = 0 gives (x – 2)(x – 3) = 0, so x = 2 or 3. |
| 3 | 25 | The discriminant is b^2 – 4ac = 9 – 4 x 2 x (-2) = 9 + 16 = 25. |
| 4 | Two | The discriminant is 36 – 32 = 4, which is positive, so there are two distinct real roots. |
| 5 | Opens downward, a = -1 | The coefficient of x^2 is -1; a negative value means the curve opens downward. |
| 6 | No contact (discriminant = -16) | The discriminant is 4 – 20 = -16, which is negative, so there is no real root and the curve stays above the axis. |
| 7 | x = -1 | The roots are 2 and -4, and the axis lies midway: x = (2 – 4) / 2 = -1. |
| 8 | x = 3 or 4 | Factorising gives (x – 3)(x – 4) = 0, so the curve crosses the x-axis at x = 3 and x = 4. |
| 9 | (x – 4)(x + 1) | Two numbers with product -4 and sum -3 are -4 and 1, giving (x – 4)(x + 1). |
| 10 | None (discriminant = -36) | Here b = 0, so the discriminant is 0 – 4 x 1 x 9 = -36; it is negative and there is no contact. |
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