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S4 Maths quadratic graphs paper 4: ten common slips taken apart

S4 Maths quadratic graphs paper 4: ten common slips taken apart

  • 2026-11-10

S4 Maths quadratic graphs paper 4: ten common slips taken apart

Ten items target the slips seen most often earlier: intercept order, discriminant arithmetic, the axis sign, repeated roots and always-positive conditions.

Direct answers Items 01 to 03 rebuild the y-intercept, a discriminant and the opening direction, 04 to 06 a repeated root, the axis sign and an equation from two roots, 07 to 09 an outside-the-roots set, the twin always-positive conditions and tangency for m, and 10 a missing negative branch.

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 25
Difficulty mix Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1
Chapter Chapter: S4 Maths Quadratic Graphs
Level S4

02 Questions (10 items)

  1. FoundationWhere does the graph of y = x^2 – 6x + 5 meet the y-axis?
  2. FoundationFind the discriminant of x^2 – 5x + 6 = 0 and state the number of real roots.
  3. FoundationGive the opening direction and the vertex of y = -2(x – 1)^2 + 8.
  4. IntermediateSolve x^2 + 10x + 25 = 0.
  5. IntermediateFind the axis of symmetry of y = x^2 + 6x + 1.
  6. IntermediateA quadratic with leading coefficient 1 has roots 3 and 5. Write the equation.
  7. ChallengeSolve the inequality x^2 – 2x – 3 > 0.
  8. ChallengeThe inequality kx^2 + 4x + 2 > 0 holds for every real x. Find the range of k.
  9. ChallengeThe curve y = x^2 – 4x + m touches the x-axis. Find m.
  10. Error redoError drill: solve x^2 <= 16. A student wrote x <= 4. What is the correct set?

03 Answers and one-line notes

# Answer One-line note
1 (0, 5) Putting x = 0 gives y = 5, so the point is (0, 5) and not the reversed (5, 0).
2 Discriminant = 1, so there are two distinct real roots The discriminant is 25 – 24 = 1, which is positive, so the two roots are distinct.
3 It opens downward and the vertex is (1, 8) The coefficient of x^2 is -2, so the curve opens downward, and the vertex form gives the vertex (1, 8) directly.
4 x = -5 (a repeated root) The left side is (x + 5)^2, so the only root is -5 and not plus or minus 5.
5 x = -3 Completing the square gives (x + 3)^2 – 8, so the axis is x = -3 and the sign flips.
6 x^2 – 8x + 15 = 0 The sum is 8 and the product 15, so the equation is x^2 – 8x + 15 = 0.
7 x < -1 or x > 3 Factorising gives (x – 3)(x + 1) > 0, and the curve opens upward, so it is positive outside the roots.
8 k > 2 It needs k > 0 together with discriminant 16 – 8k < 0, and the two conditions give k > 2.
9 m = 4 Touching means a zero discriminant: 16 – 4m = 0, hence m = 4.
10 -4 <= x <= 4 The inequality means |x| <= 4, so both directions are needed; writing only x <= 4 wrongly keeps values such as -3.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

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