S4 Maths sine and cosine rule paper 2: reverse work and applications
- 2026-11-10
S4 Maths sine and cosine rule paper 2: reverse work and applications
Ten items on reverse angles, area from three sides and parallelogram diagonals, including the two-solution case.
Direct answers Items 01 to 03 reverse the two rules, 04 to 06 area, Heron and a parallelogram, 07 to 09 the ambiguous case, finding the third angle first and the 13-14-15 area, and 10 a wrong sign in the cosine rule.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S4 Maths Sine and Cosine Rule |
| Level | S4 |
02 Questions (10 items)
- FoundationIn a triangle a = 10 cm, A = 45 and B = 60. Find b.
- FoundationIn a triangle b = 9 cm, c = 5 cm and A = 120. Find a.
- FoundationThe three sides of a triangle are a = 7 cm, b = 8 cm and c = 9 cm. Find A.
- IntermediateTwo sides of a triangle are 8 cm and 10 cm and the area is 20 cm². Find all possible values of the included angle C.
- IntermediateThe sides of a triangle are 5 cm, 6 cm and 7 cm. Find its area.
- IntermediateA parallelogram has sides 6 cm and 8 cm with an angle of 60 degrees between them. Find its longer diagonal.
- ChallengeIn a triangle a = 10 cm, b = 12 cm and A = 35. How many solutions are there, and what is B?
- ChallengeIn a triangle A = 30, B = 105 and c = 8 cm. Find a.
- ChallengeThe sides of a triangle are 13 cm, 14 cm and 15 cm. Find its area.
- Error redoA student writes a^2 = b^2 + c^2 + 2bc cosA and gets a = 10.4 cm for b = 5, c = 7 and A = 60. What is wrong, and what is the correct value?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 12.2 cm | b = a sinB / sinA = 10 x sin60 / sin45 = 12.2 cm; each side must be paired with its own opposite angle. |
| 2 | 12.3 cm | a^2 = 81 + 25 – 2 x 45 x cos120 = 106 + 45 = 151, so a = 12.3 cm; the obtuse angle makes the subtracted term positive. |
| 3 | 48.2 degrees | cosA = (64 + 81 – 49) / (2 x 8 x 9) = 0.667, so A = 48.2 degrees; the denominator is 2bc, never 2a. |
| 4 | 30 or 150 degrees | sinC = 2 x 20 / (8 x 10) = 0.5, so C is 30 or 150 degrees and both give the same area. |
| 5 | 14.7 cm² | s = (5 + 6 + 7) / 2 = 9, so the area is sqrt(9 x 4 x 3 x 2) = 14.7 cm². |
| 6 | 12.2 cm | d^2 = 36 + 64 + 2 x 48 x cos60 = 148, so d = 12.2 cm; the longer diagonal of a parallelogram uses a plus sign. |
| 7 | Two solutions: B = 43.5 or 136.5 degrees | The altitude h = b sinA = 6.9 cm is less than a = 10 cm while a is less than b, so there are two solutions, B = 43.5 or 136.5 degrees. |
| 8 | 5.66 cm | C = 180 – 30 – 105 = 45 degrees, then a = c sinA / sinC = 8 x sin30 / sin45 = 5.66 cm; find the third angle first. |
| 9 | 84 cm² | s = 21, so the area is sqrt(21 x 8 x 7 x 6) = 84 cm²; the Heron route is faster than finding an angle first. |
| 10 | The middle sign must be minus; a = 6.24 cm | a^2 = 25 + 49 – 35 = 39, so a = 6.24 cm; the plus sign belongs only to the diagonal of a parallelogram. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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