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S4 Physics Force and Motion Practice Paper (Set 1): 10 Questions with Answers on v = u + at, F = ma and Velocity-Time Graphs

S4 Physics Force and Motion Practice Paper (Set 1): 10 Questions with Answers on v = u + at, F = ma and Velocity-Time Graphs

  • 2026-11-01

S4 Physics Force and Motion Practice Paper (Set 1): 10 Questions with Answers on v = u + at, F = ma and Velocity-Time Graphs

Ten force and motion questions moving from the uniform acceleration formula to Newton’s second law and the area under a velocity-time graph, each with an answer and a one-line explanation.

Direct answers This paper has 10 questions covering uniformly accelerated motion, Newton’s laws of motion and the area under a graph; suggested time is 20 minutes.

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 20 minutes
Difficulty mix Foundation 3 · Intermediate 4 · Challenge 2 · Error redo 1
Chapter S4 Physics: Force and Motion
Level S4 (DSE)

02 Questions (10 items)

  1. FoundationA car starts from rest and accelerates uniformly at 2 m/s^2 for 5 s. What is its final velocity?
  2. FoundationA body of mass 4 kg experiences a net force of 20 N. What is its acceleration?
  3. FoundationWhat is the difference between velocity and speed?
  4. IntermediateA stone falls freely (g = 10 m/s^2, air resistance neglected). After 3 s, what are its speed and the distance fallen?
  5. IntermediateA 1,000 kg car accelerates from 0 to 20 m/s in 8 s. What are its acceleration and the net force required?
  6. IntermediateOn a velocity-time graph the velocity rises uniformly from 0 to 20 m/s in 8 s. What does the area under the line represent, and what is its value?
  7. IntermediateHow does Newton’s third law describe a pair of forces?
  8. ChallengeWhat is the weight of a 5 kg instrument on the surface of the Moon (g = 1.6 m/s^2)?
  9. ChallengeA ball is thrown vertically upwards at 20 m/s (g = 10 m/s^2). How long does it take to reach the highest point, and how high is that point?
  10. Error redoIs it true that a body moving at constant velocity must have no forces acting on it?

03 Answers and one-line notes

# Answer One-line note
1 v = u + at = 0 + 2 x 5 = 10 m/s. Write down the known quantities first, then substitute into the formula.
2 a = F / m = 20 / 4 = 5 metres per second squared. Newton’s second law: acceleration is directly proportional to net force.
3 Velocity is a vector, so it gives both how fast the body moves and in which direction; speed gives magnitude only. A change of direction is a change of velocity.
4 Speed = 10 x 3 = 30 m/s, distance = half of 10 x 3 squared = 45 m. Free fall has a constant acceleration, so the uniform acceleration formulas apply.
5 a = 20 / 8 = 2.5 metres per second squared, F = ma = 1,000 x 2.5 = 2,500 N. Find the acceleration first, then multiply by the mass.
6 It represents the displacement; the area of the triangle is half of 8 x 20 = 80 m. The area under the line is the displacement.
7 Action and reaction are equal in magnitude, opposite in direction, act on two different bodies and appear at the same time. The two forces act on different bodies, so they do not cancel.
8 W = mg = 5 x 1.6 = 8 N. Mass stays the same; weight changes with the gravitational acceleration.
9 t = u / g = 20 / 10 = 2 s, height = half of 10 x 2 squared = 20 m. At the highest point the velocity is zero, and only then does the ball fall back.
10 No. A body in uniform straight-line motion has zero net force, but equal and opposite forces may still act on it and cancel out. Zero net force does not mean no forces.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

Work through the ten questions first, then check every answer against the one-line note and bring the ones you missed to your next lesson.Tutor Registration →

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